Answer:
Explanation:
We shall apply Ampere's circuital law to find out magnetic field . It is given as follows.
∫B.dl = μ₀ I , B is magnetic field , I is current , μ₀ is permeability .
Radius of the wire r = 1.2 x 10⁻³ m
magnetic field B will be circular in shape around the wire. If B is uniform
∫B.dl = B x 2πr
B x 2πr = μ₀ I
B = μ₀ I / 2πr
= 4π x 10⁻⁷ x 37 /2πx1.2 x 10⁻³
= 10⁻⁷ x 2x37 / 1.2 x 10⁻³
= 61.67 x 10⁻⁴ T
= 62 x 10⁻⁴ T
Answer:
180,000
Explanation:
Frequency is a quantity that is measured in Hertz [Hz] and it represents the number of rotations per second.
A motor with a frequency of 50 Hz will rotate 50 times per second.
Since we don't want to know how many times it rotates per second, but per hour. The first step is to find how many seconds there are in an hour and then multiply that amount by 50.
Seconds in an hour:
there are 60 seconds per minute, and 60 minutes per hour, thus there are
60*60 = <u>3,600 seconds in an hour</u>
We know that the motor will rotate 50 times per second so to find the number of rotations in 1 hour = 3,600 seconds we multiply:
50*3,600 = 180,000 rotations
Answer:
Explanation:
Let the amplitude of individual wave be I and resultant amplitude be 1.703 I . Let the phase difference be Ф in terms of degree
From the formula of resultant vector
(1.703I)² = I² + I² + 2 I² cosФ
2.9 I² = 2I² + 2 I² cosФ
.9I² = 2 I² cosФ
cosФ = .9 / 2
= .45
Ф = 63.25 .
