Answer:
y=25.5
Step-by-step explanation:
To find y, you need to get it by itself. Ask yourself, what is being done to y, then to undo that, do the opposite. For example, if 3 was added to y, you would need to subtract 3 to cancel out the 3. In this case, what is being done to y? It's being divided by 3. So, you multiply by 3 to cancel that out. Whatever you do to one side of an equation, you also have to do to the other. So,
8.5=
Multiply both sides by 3
3(8.5) = 3(
) multiply on the left side, and on the right side the 3s cancel out
25.5=y
SOLUTION:
To begin with, let's establish the problem as the following:
5 + 7
An effective method to solve this problem would be to convert it into a visual representation in order to obtain a better understanding.
As attached in the diagram above, I have demonstrated the problem visually. The five red circles / dots represent the five in the problem whilst the 7 circles / dots represent the 7 in the problem. Now we must simply count each of the circles / dots to obtain the total number which would be our final answer.
We can also simply use our fingers on our hands to solve the problem by counting 5 on our fingers and then adding 7 or vice versa to obtain the final answer.
FINAL ANSWER:
Hence, through either of these two methods, we obtain the final answer to the problem as follows:
5 + 7 = 12
Hope this helps! :)
Have a lovely day! <3
Answer:
its A and i am sure her is the explanation
Step-by-step explanation:
- m<19-4
- m<15
The weight of an object is the product of its mass and the acceleration of gravity.
If g[e] is the acceleration of gravity on earth, and g[M] the same for Mars and g[m] the same for the moon,
then m[M]=m[e]g[M]/g[e] and m[m]=m[e]g[m]/g[e] where m[ ] denotes mass. Note that weight=mg (measured in newtons) while mass is in kilograms.
If g[M]=g[e]/3 and g[m]=g[e]/6 approximately. Then the weight of an object on Mars will be about a third of what it is on earth, while on the moon it would be about a sixth of what it is on earth.
I think it wold be b
please tell me if i wrong