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3 years ago

Plz help me with this

Mathematics

1 answer:

Lady_Fox [76]3 years ago

5 0

Basically it’s asking when is the function g(x) greater than the function of f(x), which are both graphed on the graph. g(x) needs to be above f(x) for it to be greater, and that is shows between 0-2 and 4+, making the answer A

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I dont understand and this is very urgent so can someone help me out please?

wariber [46]

Answer:

Please Find the solution below

Step-by-step explanation:

Let us say the two equations are

x+y=5 --------------(A)

x-y=1 -------------(B)

Let us solve them for x and y by adding them

2x=6

x=3

Hence from (A)

3+y=5

y=2

Hence our solution is

x=3, y=2

Adding same number to equation (A) say 2 we get

x+y+2=5+2

x+y=5+2-2

x+y=5

Hence equation remains the same while adding same number to each side.

Same thing happens if we add same number to equation (B)

Hence we draw the conclusion that the solution remains the same if same number is added to each side of the original equation.

6 0

3 years ago

Please help me . What is x equal to?

777dan777 [17]

Answer:

1. x = 2

2. x = 6

3. x = 6

4. x = 1

Step-by-step explanation: i think thats it

8 0

3 years ago

Read 2 more answers

I don’t know how to solve this

V125BC [204]

Assuming that both triangles are an exact copy of one another, it is safe to assume that 3y-7 is equal to 41. Set up an equation

3y-7=41

Add 7 to both sides

3y=48

Divide both sides by 3

y=16

Now to find PN.

Based on what we know, we can assume that MP = PN. Let's make some equations!

MP = 17x-8 PN = 11x+4

17x-8 = 11x+4

Subtract 11x from both sides

6x-8 = 4

Add 8 to both sides

6x = 12

Divide by 2

x=2

Substitute 2 in for x in the equation for PN

11(2)+4

Multiply 11 by 2

22+4 = 26

PN = 26

7 0

3 years ago

Use spherical coordinates. Find the volume of the solid that lies within the sphere x^2 + y^2 + z^2 = 81, above the xy-plane, an

Natasha_Volkova [10]

Answer:

The volume of the solid is 243 $\sqrt{2} \ \pi$

Step-by-step explanation:

From the information given:

BY applying sphere coordinates:

0 ≤ x² + y² + z² ≤ 81

0 ≤ ρ² ≤ 81

0 ≤ ρ ≤ 9

The intersection that takes place in the sphere and the cone is:

$x^2 +y^2 ( \sqrt{x^2 +y^2 })^2 = 81$

$2(x^2 + y^2) =81$

$x^2 +y^2 = \dfrac{81}{2}$

Thus; the region bounded is: 0 ≤ θ ≤ 2π

This implies that:

$z = \sqrt{x^2+y^2}$

ρcosФ = ρsinФ

tanФ = 1

Ф = π/4

Similarly; in the X-Y plane;

z = 0

ρcosФ = 0

cosФ = 0

Ф = π/2

So here; $\dfrac{\pi}{4} \leq \phi \le \dfrac{\pi}{2}$

Thus, volume: $V = \iiint_E \ d V = \int \limits^{\pi/2}_{\pi/4} \int \limits ^{2\pi}_{0} \int \limits^9_0 \rho ^2 \ sin \phi \ d\rho \ d \theta \ d \phi$