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Iteru [2.4K]
3 years ago
9

Plz help me with this

Mathematics
1 answer:
Lady_Fox [76]3 years ago
5 0
Basically it’s asking when is the function g(x) greater than the function of f(x), which are both graphed on the graph. g(x) needs to be above f(x) for it to be greater, and that is shows between 0-2 and 4+, making the answer A
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HELP ASAP.....NO LINKS AND NO TROLLING
Vadim26 [7]

Answer:

B. The graph of g(x) is narrower than the graph of f(x)

D.The graph g(x) is 8 units above the graph of f(x)

check the image given below.

  • The blue line refers to graph g(x)
  • The red line refers to graph f(x)

6 0
2 years ago
Read 2 more answers
Tanθ=sinθ/cosθ<br><br> True or False
Sedbober [7]
If;
A = Adjacent
O = Opposite
H = Hypotenuse

Then,
Sin Ф = O/H
Cos Ф = A/H
Therefore,
(Sin Ф)/Cos Ф) = (O/H)/(A/H) = (O/H)*(H/A) = O/A

Now,
tan Ф = O/A ----

Therefore, it is true that
tan Ф = SinФ/CosФ
5 0
3 years ago
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QUESTION IN THE ATTACHMENT
eimsori [14]

Answer:

A. The sum of the first 10th term is 100.

B. The sum of the nth term is n²

Step-by-step explanation:

Data obtained from the question include:

Sum of 20th term (S20) = 400

Sum of 40th term (S40) = 1600

Sum of 10th term (S10) =..?

Sum of nth term (Sn) =..?

Recall:

Sn = n/2[2a + (n – 1)d]

Sn is the sum of the nth term.

n is the number of term.

a is the first term.

d is the common difference

We'll begin by calculating the first term and the common difference. This is illustrated below:

Sn = n/2 [2a + (n – 1)d]

S20 = 20/2 [2a + (20 – 1)d]

S20= 10 [2a + 19d]

S20 = 20a + 190d

But:

S20 = 400

400 = 20a + 190d .......(1)

S40 = 40/2 [2a + (40 – 1)d]

S40 = 20 [2a + 39d]

S40 = 40a + 780d

But

S40 = 1600

1600 = 40a + 780d....... (2)

400 = 20a + 190d .......(1)

1600 = 40a + 780d....... (2)

Solve by elimination method

Multiply equation 1 by 40 and multiply equation 2 by 20 as shown below:

40 x equation 1:

40 x (400 = 20a + 190d)

16000 = 800a + 7600. ........ (3)

20 x equation 2:

20 x (1600 = 40a + 780d)

32000 = 800a + 15600d......... (4)

Subtract equation 3 from equation 4

Equation 4 – Equation 3

32000 = 800a + 15600d

– 16000 = 800a + 7600d

16000 = 8000d

Divide both side by 8000

d = 16000/8000

d = 2

Substituting the value of d into equation 1

400 = 20a + 190d

d = 2

400 = 20a + (190 x 2)

400 = 20a + 380

Collect like terms

400 – 380 = 20a

20 = 20a

Divide both side by 20

a = 20/20

a = 1

Therefore,

First term (a) = 1.

Common difference (d) = 2.

A. Determination of the sum of the 10th term.

First term (a) = 1.

Common difference (d) = 2

Number of term (n) = 10

Sum of 10th term (S10) =..?

Sn = n/2 [2a + (n – 1)d]

S10 = 10/2 [2x1 + (10 – 1)2]

S10 = 5 [2 + 9x2]

S10 = 5 [2 + 18]

S10 = 5 x 20

S10 = 100

Therefore, the sum of the first 10th term is 100.

B. Determination of the sum of the nth term.

First term (a) = 1.

Common difference (d) = 2

Sum of nth term (Sn) =..?

Sn = n/2 [2a + (n – 1)d]

Sn = n/2 [2x1 + (n – 1)2]

Sn = n/2 [2 + 2n – 2]

Sn = n/2 [2 – 2 + 2n ]

Sn = n/2 [ 2n ]

Sn = n²

Therefore, the sum of the nth term is n²

6 0
3 years ago
What is the area of triangle ABC?
Ann [662]

Answer:

A = 3 units^2

Step-by-step explanation:

The area of a triangle is

A  = 1/2 bh where b is the length of the base and h is the height

b = the distance from B to C = 4 units = 2  ( watch the scale)

h = the distance from A to C along the x axis =6 units = 3  (watch the scale)

A = 1/2 (2)(3)

A = 3 units^2

7 0
3 years ago
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Solve the proportion using equivalent ratios. Explain the steps you used to solve the proportion, and include the answer in your
rodikova [14]

Answer: Your answer is X=6

Step-by-step explanation:

10/3 = 20/x

Determine the defined range

10/3 20/x, x=0

Cross-multiply

10x = 60

Divide both sides by 10

x=6,x=0

Check if the solution is in the defined range

SOLUTION x=6

<u><em>I HOPE THIS HELPS IF NOT THE SORRY</em></u>

<u><em></em></u>

4 0
3 years ago
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