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Temka [501]
3 years ago
8

The gas in the piston is at constant temperature. A student increases the pressure on the piston from 2 atm to 3 atm. The observ

ation will be summarized in a row of the incomplete table below. mc026-1.jpg Row Name Observation Constants 1 Boyle's law ? ? 2 Charles’s law ? ? 3 Gay-Lussac’s law ? Volume, moles of gas 4 Combined gas law ? ? Which row of the table and which observation would the student fill? row 1, volume decreases when temperature decreases row 1, volume decreases when pressure increases row 3, volume decreases when temperature decreases row 3, volume decreases when pressure increases
Chemistry
2 answers:
blagie [28]3 years ago
6 0

Answer:

Option B) Row 1, Volume decreases when pressure increases.

Explanation:

azamat3 years ago
5 0
Answer : Option B) Row 1, Volume decreases when pressure increases.

Explanation : According to the boyle's law, when the pressure  of the gas molecules are increased from  2 atm to  3 atm creates a decrease in volume of the gas which then increases the rate of collision of the molecules and makes it more compact than it was before.
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A chemist designs a galvanic cell that uses these two half-reactions:
Nonamiya [84]

Answer :

(a) Reaction at anode (oxidation) : 4Fe^{2+}\rightarrow 4Fe^{3+}+4e^-  

(b) Reaction at cathode (reduction) : O_2+4H^++4e^-\rightarrow 2H_2O  

(c) O_2+4H^++4Fe^{2+}\rightarrow 2H_2O+4Fe^{3+}

(d) Yes, we have have enough information to calculate the cell voltage under standard conditions.

Explanation :

The half reaction will be:

Reaction at anode (oxidation) : Fe^{2+}\rightarrow Fe^{3+}+e^-     E^0_{anode}=+0.771V

Reaction at cathode (reduction) : O_2+4H^++4e^-\rightarrow 2H_2O     E^0_{cathode}=+1.23V

To balance the electrons we are multiplying oxidation reaction by 4 and then adding both the reaction, we get:

Part (a):

Reaction at anode (oxidation) : 4Fe^{2+}\rightarrow 4Fe^{3+}+4e^-     E^0_{anode}=+0.771V

Part (b):

Reaction at cathode (reduction) : O_2+4H^++4e^-\rightarrow 2H_2O     E^0_{cathode}=+1.23V

Part (c):

The balanced cell reaction will be,

O_2+4H^++4Fe^{2+}\rightarrow 2H_2O+4Fe^{3+}

Part (d):

Now we have to calculate the standard electrode potential of the cell.

E^o=E^o_{cathode}-E^o_{anode}

E^o=(1.23V)-(0.771V)=+0.459V

For a reaction to be spontaneous, the standard electrode potential must be positive.

So, we have have enough information to calculate the cell voltage under standard conditions.

4 0
3 years ago
Iron has a known density of 7.87 g/cm3. What would be the mass of a 2.5<br> cm3 piece of iron?
Fudgin [204]
If i am not mistaken ,

density = mass / volume

density = 7.87 g/cm3
volume = 2.5 cm3

thus ,
mass = density x volume

7.87 g/cm3 x 2.5 cm3 = 19.675 g
5 0
3 years ago
Explain how you would make 500ml of a 0.100 m naoh solution
icang [17]
Molar mass NaOH =23+16+1=40 g/mol
<span> 0.100 M= 0.100 mol/L
</span>500 ml=0.500 L
0.500L*0.100 mol/L=0.0500 mol NaOH we need to prepare 500 ml solution
0.0500 mol NaOH*40g/1mol=2 g NaOH we need to prepare 500 ml solution
we need  2 g NaOH, dissolve it in small amount of water, and dilute it with water up to 500 mL
3 0
3 years ago
What is the percent oxygen in Rb2Cr2O7
blondinia [14]

Answer:

28.9452

Explanation:

8 0
3 years ago
Read 2 more answers
What is the ratio of carbon, hydrogen, and oxygen in most carbohydrates?
horrorfan [7]
 In carbohydrates the C:H:O is 1:2:1
7 0
3 years ago
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