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igomit [66]
3 years ago
5

Cu2(s)+O2(g)=Cu2O(g)+SO2(g)please help urgent will give brainiest​

Chemistry
1 answer:
AysviL [449]3 years ago
3 0

Answer:

2 Cu2S + 3 O2 = 2 Cu2O + 2 SO2

Explanation:

2 Cu2S + 3 O2 = 2 Cu2O + 2 SO2

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In any nuclear reaction, nuclei are transformed in some way.<br> TRUE<br> FALSE
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Yep that is true. These are rxns that change the nucleus
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Write the balanced molecular equation for the neutralization reaction between hi and ba(oh)2 in aqueous solution. include physic
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So, Ba is divalent. This means that each Ba(OH)2 requires two I in order to produce one BaI2 molecule.
The two hydrogens from the 2 HI molecules will combine with 2 OH of Ba(OH)2 forming 2 water (H2O) molecules.

The equation which illustrates this reaction in as follows:
<span>2 HI (aq) + Ba(OH)2 (s) ........> BaI2 (aq) + 2 H2O (l)
</span>where:
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l refers to liquid state.
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Groups on the Periodic Tables have the same number of valence electrons which affects
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Answer:

The vertical columns (group) of the periodic table are arranged such that all it's elements have the same number of valence electrons. All elements within a certain group thus group share similar properties.

8 0
3 years ago
Complete the following analogy:
Jlenok [28]
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A large cylindrical tank contains 0.750 m3 of nitrogen gas at 27°C and 7.50 * 103 Pa (absolute pressure). The tank has a tight‐f
Nuetrik [128]

Answer: The answer is 68142.4 Pa

Explanation:

Given that the initial properties of the cylindrical tank are :

Volume V1= 0.750m3

Temperature T1= 27C

Pressure P1 =7.5*10^3 Pa= 7500Pa

Final properties of the tank after decrease in volume and increase in temperature :

Volume V2 =0.480m3

Temperature T2 = 157C

Pressure P2 =?

Applying the gas law equation (Charles and Boyle's laws combined)

P1V1/T1 = P2V2/T2

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P2 =(7500 * 0.750* 157) / (0.480 *27)

P2 = 883125/12.96

P2 = 68142.4Pa

Therefore the pressure of the cylindrical tank after decrease in volume and increase in temperature is 68142.4Pa

8 0
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