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3 years ago

Please help Find: ∠x ∠a ∠b

Mathematics

1 answer:

V125BC [204]3 years ago

7 0

Answer:

your answer

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Sliva [168]

Answer:5.83k

Step-by-step explanation:

annual means divide current by 6

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3 years ago

How many grams of barium chloride are there in 0.200 moles

Anni [7]

There are 41.646600000013 grams of barium chloride in 0.200 moles

5 0

3 years ago

How Do You Write .0676767 In Scientific Notation?

evablogger [386]

6.8 x 10^-2

The scientific notation of 70, 030, 000. To find the scientific notation of this value 
1. We first move the period which separates the whole number from the decimal number which is located after the numbers of the given value.
2. We move it in the very recent order number which is seventy million, seven and zero. 
3. It becomes 7.003
4. Thus we count how many moves we did from the tens to the ten million order place. 
5. 7.003 x 10^7

4 0

3 years ago

Which equation would help you find the missing side length in the right triangle shown?

irina [24]

Equation a^2 + b^2 = c^2
c = longest side, unknown
The answer is D.
12^2 + 10^2 = c^2

7 0

2 years ago

Two different radioactive isotopes decay to 10% of their respective original amounts. Isotope A does this in 33 days, while isot

Andrews [41]

Answer:

The approximate difference in the half-lives of the isotopes is 66 days.

Step-by-step explanation:

The decay of an isotope is represented by the following differential equation:

$\frac{dm}{dt} = -\frac{t}{\tau}$

Where:

$m$ - Current mass of the isotope, measured in kilograms.

$t$ - Time, measured in days.

$\tau$ - Time constant, measured in days.

The solution of the differential equation is:

$m(t) = m_{o}\cdot e^{-\frac{t}{\tau} }$

Where $m_{o}$ is the initial mass of the isotope, measure in kilograms.

Now, the time constant is cleared:

$\ln \frac{m(t)}{m_{o}} = -\frac{t}{\tau}$

$\tau = -\frac{t}{\ln \frac{m(t)}{m_{o}} }$

The half-life of a isotope ( $t_{1/2}$ ) as a function of time constant is:

$t_{1/2} = \tau \cdot \ln2$

$t_{1/2} = -\left(\frac{t}{\ln\frac{m(t)}{m_{o}} }\right) \cdot \ln 2$

The half-life difference between isotope B and isotope A is:

$\Delta t_{1/2} = \left| -\left(\frac{t_{A}}{\ln \frac{m_{A}(t)}{m_{o,A}} } \right)\cdot \ln 2+\left(\frac{t_{B}}{\ln \frac{m_{B}(t)}{m_{o,B}} } \right)\cdot \ln 2\right|$

If $\frac{m_{A}(t)}{m_{o,A}} = \frac{m_{B}(t)}{m_{o,B}} = 0.9$ , $t_{A} = 33\,days$ and $t_{B} = 43\,days$ , the difference in the half-lives of the isotopes is:

$\Delta t_{1/2} = \left|-\left(\frac{33\,days}{\ln 0.90} \right)\cdot \ln 2 + \left(\frac{43\,days}{\ln 0.90} \right)\cdot \ln 2\right|$

$\Delta t_{1/2} \approx 65.788\,days$

The approximate difference in the half-lives of the isotopes is 66 days.

4 0

3 years ago

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