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Veseljchak [2.6K]
3 years ago
13

Which is an asymptote of the graph of the function y = cot ( x - 2pi / 3 )

Mathematics
2 answers:
Sloan [31]3 years ago
8 0
The answer to the equation is b
Butoxors [25]3 years ago
6 0

Answer with explanation:

we have to find the Asymptote of the function:

  y=\cot(x-\frac{2\pi}{3})

As  period of cot x is equal to [-π, π].

 x-\frac{2\pi}{3}=0\\\\x=\frac{2\pi}{3}\\\\ x-\frac{2\pi}{3}=\pi\\\\x=\frac{2\pi}{3}+\pi \\\\x=\frac{5\pi}{3} \\\\x=\cot(2\pi -\frac{\pi}{3})\\\\x=\frac{-\pi}{3}

You can find asymptote by drawing the graph of

     y=\cot(x-\frac{2\pi}{3})

There are two Asymptotes

1.\rightarrow x= \frac{-\pi}{3}\\\\2..\rightarrow x= \frac{2\pi}{3}

Out of the four option

⇒Option B

          x=\frac{-\pi}{3} is one asymptote of the graph.

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What is the value of the remainder if 10x4 – 6x3 + 5x2 – x + 1 is divided by x – 3?
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Step-by-step explanation:

Given function is 10x^4-6x^3+5x^2-x+1.

Now we need to find remainder if we divide given function 10x^4-6x^3+5x^2-x+1 by (x-3)

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