The answer would be 24.0 because it is such a precise measurement.
<span>What type of energy is released when fossil fuels are burned?
a.
electrical energy</span>
The molar concentration of the KI_3 solution is 0.0833 mol/L.
<em>Step 1</em>. Calculate the <em>moles of S_2O_3^(2-)</em>
Moles of S_2O_3^(2-) = 25.00 mL S_2O_3^(2-) ×[0.200 mmol S_2O_3^(2-)/(1 mL S_2O_3^(2-)] = 5.000 mmol S_2O_3^(2-)
<em>Step 2</em>. Calculate the <em>moles of I_3^(-)
</em>
Moles of I_3^(-) = 5.000 mmol S_2O_3^(2-)))) × [1 mmol I_3^(-)/(2 mmol S_2O_3^(2-)] = 2.500 mmol I_3^(-)
<em>Step 3</em>. Calculate the <em>molar concentration of the I_3^(-)</em>
<em>c</em> = "moles"/"litres" = 2.500 mmol/30.00 mL = 0.083 33 mol/L
Ahh the charges! I know just how to help!!
One thing I do is I draw each individual proton or electron out. Make sure you label each proton with a + and each electron with a -.
Then I cross them out. For each proton you cross out, cross out an electron and vice-versa.
If you end with a proton, then the atom is positive.
If you end with an electron, then the atom is negative.
If you end with nothing, then it is neutral.
HOPE THIS HELPS!!!!!! Let me know if you have more questions!!