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SCORPION-xisa [38]

4 years ago

13

Some of the water you spilled on your shirt evaporates

1 answer:

Montano1993 [528]4 years ago

5 0

Answer:

No

Explanation:

In my opinion water doesn't evaporates when is spills on a fabric or a shirt someone is wearing. The fabric or cloth whatever you may call it sucks the water, making you feel your shirt wet. But as the time passes it will slowly dry due to the sun or the warmth surrounding the area the fabric is at.

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What else is produced when sodium carbonate decomposes?<br><br> Na2CO3 → Na2O + <br> _________

cricket20 [7]

Answer:

CO2

cardon dioxide is produced

3 0

3 years ago

At which temperature will the least amount of time pass before someone detects the odor of a fragrant flower?

NARA [144]

0C, 8C, 29C, 15C. I think

7 0

4 years ago

Which of these molecules is nonpolar?<br> a.CH3CI<br> b.CO<br> c.O2<br> d.PF3

valentina_108 [34]

Answer:

i think the answer is D

Explanation:

7 0

2 years ago

Read 2 more answers

The equilibrium constant, K., for the following reaction is 83.3 at 500 K. PC13(g) + Cl2(g) = PC13(E) Calculate the equilibrium

lord [1]

Answer:

The equilibrium concentration of $PCl_5=0.228 M$ .

The equilibrium concentration of $PCl_3=0.280 M -0.228 M=0.052M$ .

The equilibrium concentration of $Cl_2=0.280 M -0.228 M=0.052M$ .

Explanation:

Answer:

The equilibrium concentration of HCl is 0.01707 M.

Explanation:

Equilibrium constant of the reaction = $K_c=83.3$

Moles of $PCl_3 = 0.280 mol$

Concentration of $[PCl_3]=\frac{0.280 mol}{1.00 L}=0.280 M$

Moles of $Cl_ = 0.280 mol$

Concentration of $[Cl_2]=\frac{0.280 mol}{1.00 L}=0.280M$

$PCl_3(g)+Cl_2(g)\rightleftharpoons PCl_5(g)$

Initial: 0.280 0.280 0

At eq'm: (0.280-x) (0.280-x) x

We are given:

$[PCl_3]_{eq}=(0.280-x)$

$[Cl_2]_{eq}=(0.280-x)$

$[PCl_5]_{eq}=x$

Calculating for 'x'. we get:

The expression of $K_{c}$ for above reaction follows:

$K_c=\frac{[PCl_5]}{[PCl_3][Cl_2]}$

Putting values in above equation, we get:

$83.3=\frac{x}{(0.280-x)\times (0.280-x)}$

On solving this quadratic equation we get:

x = 0.228, 0.344

0.228 M < 0.280 M< 0.344 M

x = 0.228 M

The equilibrium concentration of $PCl_5=0.228 M$ .

The equilibrium concentration of $PCl_3=0.280 M -0.228 M=0.052M$ .

The equilibrium concentration of $Cl_2=0.280 M -0.228 M=0.052M$ .

4 0

3 years ago

The radioactive isotope 210/84 Po decays by alpha emission.

yan [13]

The half-life of polonium-210, given that it decays from 98.3 micrograms to 12.3 micrograms in 414 days is 138 days

<h3>How to determine the number of half-lives </h3>

Original amount (N₀) = 98.3 micrograms
Amount remaining (N) = 12.3 micrograms
Number of half-lives (n) =?

2ⁿ = N₀ / N

2ⁿ = 98.3 / 12.3

2ⁿ = 8

2ⁿ = 2³

n = 3

<h3>How to determine the half life </h3>

Number of half-lives (n) = 3
Time (t) = 414 days
Half-life (t½) = ?

t½ = t / n

t½ = 414 / 3

t½ = 138 days

Learn more about half life:

brainly.com/question/26374513

#SPJ1

4 0

2 years ago

Read 2 more answers