Answer is: mass of phosphorus is 37,16 grams.
m(C) = 36 g.
n(C) = m(C) ÷ M(C).
n(C) = 36 g ÷ 12 g/mol.
n(C) = 3 mol.
From balanced chemical reaction: n(C) : n(P) = 5 : 2.
n(P) = 2 · 3 mol ÷ 5.
n(P) = 1,2 mol.
m(P) = 1,2 mol · 30,97 g/mol.
m(P) = 37,16 g.
<span>75g / 1.20 = 62.5 ml.
Hope this helps :))
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Answer:
The molarity of the Pb(NO3)2 solution is 0.24 M
Explanation:
Assuming there was no loss during filtration, we can calculated amount of moles Pb(NO3)2 from the 13.25 g of PbCl2 ussing molar mass of PbCl2
13.25 g / 278.1 g = 0.04 moles of PbCl2
According balanced equation 2NaCl + Pb(NO3)2 = 2NaNO3 + PbCl2, 1 mol of Pb(NO3)2 produces 1 mol of PbCl2. So, 0.04 moles of Pb(NO3)2 produces PbCl2
Molarity is = moles of solute/volumen of solution (L)=0.04/0.2= 0.24
I hope my answer helps you
All of them are important to identify a mineral and get information from it, but I'd say the least important is cleavage.