Answer:
speed of plane in still air = 252 mph
speed of wind = 42 mph.
Explanation:
Given:
Distance travelled by the small plane = 245
Time taken to fly 245 miles = 1 hour and 10 minutes.
Time taken for return trip = 50 minutes.
To Find:
speed of the wind=?
The speed of the plane in still air=?
Solution:
We Know that
=>
=>
=>
=>210 mph against wind
on way back
=>
=>
=>
=> 294
Now
294 = plane +wind------------------------(1)
210 =plane - wind-------------------------(2)
Solving (1) and (2)
2 plane = 504
plane = 252
plane =
So substituting plane value in eq(2) we get,
210 =252 - wind
wind = 42 mph
Answer:
44.7 degree (3 s.f)
Explanation:
mass of water = 4.10Kg
Initial temperature = 37.5C
Final temperature = x
Heat = 125 kJ = 125000 J
Specific heat capacity = 4180 J/kg°C
These parameters are given by:
H = MCΔT
ΔT = H / MC
ΔT = 125000 / (4.10 * 4180)
ΔT = 7.294
ΔT = T2 - T1
T2 = ΔT + T1
T2 = 7.294 + 37.5
T2 = 44.794 = 44.7 degree (3 s.f)
The answer should be 12 since 4 x 3 = 12
This is because ammonia is NH^3 and if it has a number before it you multiply it with the rest of the chemical equation.
I hope this helps
Answer: A non-covalent interaction differs from a covalent bond in that it does not involve the sharing of electrons, but rather involves more dispersed variations of electromagnetic interactions between molecules or within a molecule. The chemical energy released in the formation of non-covalent interactions is typically on the order of 1–5 kcal/mol (1000–5000 calories per 6.02 × 10 molecules).
Explanation: