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Fofino [41]
4 years ago
7

7.3 x 10^-4 mL/s to cubic feet per day

Chemistry
1 answer:
yulyashka [42]4 years ago
4 0
Note that
1 L = 3.53147 x 10⁻² ft³, therefore
1 mL = 3.53147 x 10⁻⁵ ft³
1 day = 86400 s

Perform the conversion.
7.3 \times 10^{-4} \,  \frac{mL}{s} \\  = (7.3 \times 10^{-4}  \frac{mL}{s} )*(3.53147 \times 10^{-5} \,  \frac{ft^{3}}{mL}  )*(86400 \,  \frac{s}{day} ) \\ = 1.763 \times 10^{-3} \,  \frac{ft^{3}}{day}

Answer:  1.763 x 10⁻³ ft³/day

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A fast moving object goes a long distance in a _______ period of time
harina [27]
I believe the answer you are looking for is : SHORT
4 0
4 years ago
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explain why it is easier to separate a solid from another solid compared to a liquid from another liquid
makkiz [27]

Answer:

it is because solid is.in a fixed shape so it is easier to separate a solid from another solid compared to a liquid from another liquid

4 0
3 years ago
7. A gas has a volume of 300 mL at 300 mm Hg. What will its volume be if the pressure is changed to 500 mm Hg?​
USPshnik [31]

Answer:

The volume is

<h2>180 mL</h2>

Explanation:

In order to solve for the volume we use the formula for Boyle's law which is

<h3>P _{1}  V _{1} = P _{2}V _{2}</h3>

where

P1 is the initial pressure

V1 is the initial volume

P2 is the final pressure

V2 is the final volume

Since we are finding the final volume we are finding V2

Making V2 the subject we have

<h3>V _{2}  = \frac{P _{1}  V _{1}}{P _{2}  }</h3>

From the question

P1 = 300 mmHg

V1 = 300 mL

P2 = 500 mmHg

Substitute the values into the above formula and solve for the final volume obtained

That's

<h3>V _{2} =  \frac{300 \times 300}{500}  \\  =  \frac{90000}{500}  \\  =  \frac{900}{5}</h3>

We have the final answer as

<h3>180 mL</h3>

Hope this helps you

7 0
4 years ago
The compounds n-butane, ch3(ch2)2ch3, and trimethylamine, n(ch3)3, have very similar molecular weights. However, their melting p
Ostrovityanka [42]
<h3>Answer:</h3>

            The lowest boiling point is of n-Butane because it only experiences London Dispersion Forces between molecules.

<h3>Explanation:</h3>

                   Lets take start with the melting point of both compounds.

                                      n-Butane  =  - 140 °C

                                      Trimethylamine  =  - 117 °C

Intermolecular Forces in n-Butane:

                                                      As we know n-Butane is made up of Carbon and Hydrogen atoms only bonded via single covalent bonds. The electronegativity difference between C and C atoms is zero while, that between C and H atoms is 0.35 which is less than 0.4. Hence, the bonds in n-Butane are purely non polar in nature. Therefore, only London Dispersion Forces are found in n-Butane which are considered as the weakest intermolecular interactions.

Intermolecular Forces in Trimethylamine:

                                                             Trimethylamine (a tertiary amine) is made up of Nitrogen, Carbon and Hydrogen atoms bonded via single covalent bonds. The electronegativity difference between N and C atoms is 0.49  which is greater than 0.4. Hence, the C-N bond is polar in nature. Therefore, Dipole-Dipole interactions will be formed along with London Dispersion Forces which are stronger than Dispersion Forces. Therefore, due to Dipole-Dipole interactions Trimethylamine will have greater melting point than n-Butane.

5 0
4 years ago
How do I tell the number of Valence electrons present in an element just by looking at a periodic table?
zhuklara [117]
Look at the periodic table (Boron has 3) and count up from there
5 0
3 years ago
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