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mel-nik [20]
3 years ago
13

Describe how you would prepare 500ml of 40% (w/v) aqueous iodine solution.

Chemistry
1 answer:
VikaD [51]3 years ago
8 0

Answer:

- Weight 333.3 grams of iodine.

- Measure 500 mL of water.

- Vigorously mix the resulting solution.

Explanation:

Hello,

In this case, since 500 mL of a 40% (w/v) aqueous solution iodine is required, we can compute the required mass of iodine by defining the given mass-volume percent:

\% w/v=\frac{m_{iodine}}{m_{solution}} *100%=\frac{m_{iodine}}{m_{water}+m_{iodine}} *100%

In such a way, we need to find mass of iodine, which is computed as:

m_{iodine}=\frac{\%w/v*m_{water}}{100w/v-\%} \\\\m_{iodine}=\frac{40*500}{100-40}\\ \\m_{iodine}=333.3g\\

Thereby, the procedure will be:

- Weight 333.3 grams of iodine.

- Measure 500 mL of water.

- Vigorously mix the resulting solution.

Best regards.

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An unknown liquid has a mass of 22.1 g
Yuki888 [10]
M = 22.1 g
V = 52.3 mL
D = ?

D = m/V
= 22.1/52.3
= 22.1*10/52.3*10
= 221/523
= 0.4

There. I’m sorry i forgot what exactly was the S.I. unit of density :(
6 0
3 years ago
If there were 10 grams of a radioactive isotope, how much of the sample would be left after 1 half-life? How much after 2 half-l
Vikentia [17]
One half-life: 5 grams
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3 0
3 years ago
Select all possible answers:
Dafna11 [192]

Answer:

c and d are correct

Explanation:

In A, false because in Valence Electrons, the more the valences, the more stable an atom is.

In B, false because atoms cannot readily gain or lose valence electrons as the number of valence electrons is determined by the column they are in.

In C, true because the more the valence electrons, the more the stability of an atom.  

In D, true as electron placing is important and the reactivity of an atom is important.

So C and D are true!

7 0
3 years ago
Read 2 more answers
How do I answer and do this
Alecsey [184]

a) When the reaction takes place a yellow precipitate will be formed.

b) The law of conservation of mass is true.

<u>Explanation:</u>

a) When a lead nitrate solution is mixed with a potassium chromate solution, a yellow precipitate containing lead forms according to the equation:

Pb(NO_3)_2 (aq) + K_2CrO_4 (aq) → 2 KNO_3 (aq) + PbCrO_4(s).

b) Law of conservation of mass for the given reaction is true.

From the given table we know the mass of reactants and its products.

Law of conservation of mass is a principle when a reaction takes place in a closed system, the mass of the products and reactants in the system doesn't change.

⇒The sum of the mass of the reactants = The sum of the mass of the products.

The sum of the reactants = 128.71+128.97.

                                          = 257.68 g.

The sum of the products = 154.10+103.58.

                                          = 257.68 g.

Thus law of conservation of mass is true for the above reaction.

3 0
3 years ago
4. How many atoms are in 32.6 g of Oxygen?
Natali5045456 [20]

Hey there!

Oxygen has a molar mass of 16. That means 16g of oxygen is 1 mole.

32.6 ÷ 16 = 2.0375 moles

We have 2.0375 moles.

There are 6.022 x 10²³ atoms in one mole.

2.0375 x 6.022 x 10²³

1.3 x 10²⁴

There are 1.3 x 10²⁴ atoms in 32.6 grams of oxygen.

Hope this helps!

7 0
3 years ago
Read 2 more answers
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