Midpoint ( (x1+x2)/2, (y1+y2)/2)
( (5+-3)/2, (9+7)/2)
(2/2,16/2)
(1,8)
Answer: (1,8)
We have that
f(x)=(x-4)^2-1 in the question and f(x)=-(x-4)^2-1 in the picture
<span>so
</span><span>I'm going to analyze the two cases
</span><span>
using a graph tool
case 1)
</span>f(x)=(x-4)^2-1<span>
the vertex is the point (4,-1)
the x intercepts are the points (3,0) and (5,0)
the y intercept is the point (0,15)
</span><span>the axis of symmetry is x=4
</span>see the attached figure N 1
case 2)
f(x)=-(x-4)^2-1
the vertex is the point (4,-1)
there is no x intercepts
the y intercept is the point (0,-17)
the axis of symmetry is x=4
see the attached figure N 2
the answer <span>
considering the case N 2 </span>
isvertex (4,-1)------> is correcty intercept (0,-17)-----> is correctaxis of symmetry x=4-----> is correct
12. 4(s+5)
4s+20
15. 2(3r-12)
6r-24
18. -3(16-3d)
9d-48
Answer:
50⁰
Step-by-step explanation:
the 2 triangles are congruent, meaning the angles equal the same. angles B and S are the same, angles A and R are the same, and angles Q and C are the same (congruent)
Answer:
<h2>
The eleventh term of the sequence is 64</h2>
Step-by-step explanation:
The sequence given is an arithmetic sequence
14, 19, 24, …………., 264
The nth term of an arithmetic sequence is given as;
Tn = a+(n-1)d where;
a is the first term = 14
d is the common difference = 19-14=24-19 = 5
n is the number of terms = 11(since we are to look for the eleventh term of the sequence)
substituting the given values in the formula given;
T11 = 14+(11-1)*5
T11 = 14+10(5)
T11 = 14+50
T11 = 64
The eleventh term of the sequence is 64