I think holding steady I’m not sure!
Let the height of the building be x. Let the initial distance of the ant from the building be y, then
tan 32 = x/y
y = x/tan 32 . . . . . . . . (1)
tan 22 = x/(y + 66)
y tan 22 + 66 tan 22 = x
y = (x - 66 tan 22)/tan 22 . . . . . . . . (2)
Equating (1) and (2), we have
x/tan 32 = (x - 66 tan 22)/tan 22
x tan 22 = x tan 32 - 66 tan 22 (tan 32)
x(tan 32 - tan 22) = 66 tan 22 (tan 32)
x = (66 tan 22 (tan 32))/(tan 32 - tan 22) = 66(0.4040)(0.6249)/(0.6249 - 0.4040) = 16.6626/0.2208 = 75.4
Therefore, the height of the building is 75.4 feet.
Perpendicular lines have negative reciprocals. This means that if you multiply the slopes of both lines, the product will be a -1.
In your given point-slope equation, the slope is 1/3. Therefore, the negative reciprocal of 1/3 must be -3.
Out of the given options:
y + 2 = -3(x — 4)
y = -3x - 5
are the linear equations that are perpendicular to y — 1 = 1/3(x + 2).
Therefore, the correct answers are Options 1 and 3.
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Use photomath. it shows the work too
Answer:
x=2
Step-by-step explanation:
