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Maslowich
2 years ago
13

Number of electrons in the outer ring of bromine

Chemistry
1 answer:
Bond [772]2 years ago
8 0
Simple, 

looking at the periodic table..

1s2,2s2,2p6,3s2,3p6,4s2,3d10,4s5

Thus, there are 5 valence electrons in the outer ring of Bromine.
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4 0
2 years ago
What is the boiling point of a solution produced by adding 610 g of cane sugar (molar mass 342.3 g/mol) to 1.4 kg of water? For
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Answer:

Boiling point of solution is 100.65^{0}\textrm{C}

Explanation:

Cane sugar is a non-volatile solute.

According to Raoult's law for a non-volatile solute dissolved in a solution-

                              \Delta T_{b}=K_{b}.m

Where, \Delta T_{b} is elivation in boiling point of solution, K_{b} is ebbulioscopic constant of solvent (how much temperature is raised for dissolution of 1 mol of non-volatile solute) and m is molality of solution.

Here, K_{b}=0.51^{0}\textrm{C}.kg.mol^{-1}

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So, molality of solution (m) = \frac{1.78}{1.4}mol.kg^{-1}=1.27mol.kg^{-1}

Plug in all the values in the above equation, we get-

\Delta T_{b}=0.51^{0}\textrm{C}.kg.mol^{-1}\times 1.27mol.kg^{-1}=0.65^{0}\textrm{C}

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