Answer:

➳ You can use the <u>centrifugation</u> method to separate chemicals present in the blood.
160 g of SO3 are needed to make 400 g of 49% H2SO4.
<h3>How many grams of SO3 are required to prepare 400 g of 49% H2SO4?</h3>
The equation of the reaction for the formation of H2SO4 from SO3 is given below as follows:

1 mole of SO3 produces 1 mole of H2SO4
Molar mass of SO3 = 80 g/mol
Molar mass of H2SO4 = 98 g/mol
80 g of SO3 are required to produce 98 og 100%H2SO4
mass of SO3 required to produce 400 g of 100 %H2SO4 = 80/98 × 400 = 326.5 g of SO3
Mass of SO3 required to produce 49% of 400 g H2SO4 = 326.5 × 49% = 160 g
Therefore, 160 g of SO3 are needed to make 400 g of 49% H2SO4.
Learn more about mass and moles at: brainly.com/question/15374113
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The correct answer among the options given is B. . When
the forward and reverse paths of a change occur at the same rate, <span>the system is in equilibrium specifically in
dynamic equilibrium.<span> Dynamic equilibrium is
the balance in a process that is continuing. </span></span>
Chemical equations are equations that show that the chemical formulas of a substance that has been reacted and/or produced.
Answer:
66 grams
Explanation:
For every 1 gram of NH4NO3 equals 2 grams of water