Aluminum has a density of 2.70 g/mL. Calculate the mass (in grams) of a piece of aluminum having a volume of 417 mL .
1 answer:
Answer:
m = 1125.9 g.
Explanation:
Hey there!
In this case, according to the given information, it turns out possible for us to solve this problem by using the definition of density as mass divided by volume:
Thus, we solve for the mass in the equation to obtain:
Then, we plug in the values to obtain:
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Answer:see the image for the structure of the allylic carbocation
Explanation:
When 2,4-hexanediene is protonated at the 5-position as shown in the image, a carbonation is formed which can be stabilized by resonance. The positive charge can be found on carbon 4 or carbon 2 due to resonance of the allylic carbonation. The both structures are shown and electron movements were depicted using curved arrow notation in the structures shown in the image attached.
(i) 1 mole of Ar =6.022×10^23
atoms of Ar
52 mol of Ar=52×6.022×10 ^23
atoms of Ar =3.131×10 ^25 atoms of Ar
(ii) Atomic mass of He = 4amu
Or
4amu is the mass of He atoms = 1
Therefore 52 amu is the mass of He atoms=0.25×52=13 atoms of He
(iii) Gram atomic mass of He = 4g
Or
4g of He contains =6.022×10 ^23
atoms
Therefore 52 g of He contains=
6.022×10 ^23/4×52 =7.83×10 ^24 atoms
