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Monica [59]
3 years ago
10

Some plants have fleshy stems and leaves that can store water. In which type of habitat would these adaptations be important

Chemistry
1 answer:
azamat3 years ago
4 0
Desert most likely because your description most depicts plants most commonly found in deserts. Plus in dry climates plants tend to store water in case of a drought.
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What are inside of cars so hot when left in the sun
Naya [18.7K]

Answer:

metalllll/material

Explanation:

you know how dark shirts absorb the sun heat well its practically the same just with material.

"Why is the inside of a car so hot after sitting in the sun?

Cars warm up in the sun due to the greenhouse effect: Sunlight passing through the windows into the car is mostly absorbed by interior surfaces, then radiated back to the air as heat. ... “As a consequence, the inside of the car will warm because radiation is coming in but not much is going back out.”Jul 27, 2009

Curiosities: Does a dark-colored car heat up more in the sun than a ..."

8 0
4 years ago
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What is the Scientific<br> Method?
Doss [256]

Answer:

I just finished a unit on Scientific Method in my science class! Anyway, it's defined in the screenshots below. Hope this helps!

8 0
3 years ago
ang mga kumpanya ng electric motorcycle ay nag anunsyon na hindi na sila gagawa pa ng motor na pinaandar ng kuryente .ano sa pal
andreev551 [17]
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5 0
3 years ago
Bond length is the distance between the centers of two bonded atoms. On the potential energy curve, the bond length is the inter
mariarad [96]

Answer:

152 pm

Explanation:

According to the question, we can estimate the bond length from the given values of the atomic radii. This now is the upper limit of the bond length for the molecule.

Since we have that;

Atomic radius of H= 37.0 pm

Atomic radius of Br = 115.0 pm

Bond length = Atomic radius of H + Atomic radius of Br

Bond length = 37.0 pm + 115.0 pm

Bond length = 152 pm

5 0
3 years ago
Consider the reaction between nis2 and o2: 2nis2(s)+5o2(g)→2nio(s)+4so2(g) when 11.2 g of nis2 are allowed to react with 5.43 g
stellarik [79]
M(NiS₂) = 11.2 g.
n(NiS₂) = m(NiS₂) ÷ M(NiS₂).
n(NiS₂) = 11.2 g ÷ 122.8 g/mol.
n(NiS₂) = 0.091 mol.
m(O₂) = 5.43 g.
n(O₂) = 5.43 g ÷ 32 g/mol.
n(O₂) = 0.17 mol; limiting reactant.
From chemical reaction: n(NiS₂) : n(O₂) = 2 : 5.
0.091 mol : n(O₂) = 2 : 5.
n(O₂) = 0.2275 mol, not enough.
n(NiO) = 4.89 g .
n(O₂) : n(NiS) = 5 : 2.
n(NiS) = 0.068 mol.
m(NiS) = 0.068 mol · 74.7 g/mol = 5.08 g.
percent yield = 4.89 g / 5.08 g · 100% = 96.2%.


6 0
3 years ago
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