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Aleksandr-060686 [28]
3 years ago
13

What force is needed to propel a 421-kg car with an acceleration of 3.77 m/s2?

Physics
2 answers:
postnew [5]3 years ago
6 0

Answer:

The last one

Explanation:

F=ma

F=421×3.77=~1.59×10^3N

zheka24 [161]3 years ago
5 0

Answer:1.59 x 10^3 N

Explanation:

Force = Mass x Acceleration due to gravity.

F = 421 * 3.77 = 1.59 x 10^3 N

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MgS

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c. "Ohmic" is when the plot of I [Amp] versus V [Volt] has a slope equal to R.

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Why do mass numbers have a trailing decimal? use the following words describe for credit isotopes protons neutrons electrons in
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Who is invented compass​
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6 0
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Read 2 more answers
as you go above earths surface, the acceleration due to gravity will decrease. find the height, i meters, above the earths surfa
aleksklad [387]

Answer:

1.23×10⁸ m

Explanation:

Acceleration due to gravity is:

a = GM / r²

where G is the universal gravitational constant,

M is the mass of the planet,

and r is the distance from the center of the planet to the object.

When the object is on the surface of the Earth, a = g and r = R.

g = GM / R²

When the object is at height i above the surface, a = 1/410 g and r = i + R.

1/410 g = GM / (i + R)²

Divide the first equation by the second:

g / (1/410 g) = (GM / R²) / (GM / (i + R)²)

410 = (i + R)² / R²

410 R² = (i + R)²

410 R² = i² + 2iR + R²

0 = i² + 2iR − 409R²

Solve with quadratic formula:

i = [ -2R ± √((2R)² − 4(1)(-409R²)) ] / 2(1)

i = [ -2R ± √(1640R²) ] / 2

i = (-2R ± 2R√410) / 2

i = -R ± R√410

i = (-1 ± √410) R

Since i > 0:

i = (-1 + √410) R

R = 6.37×10⁶ m:

i ≈ 1.23×10⁸ m

8 0
3 years ago
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