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Scrat [10]
4 years ago
14

Which property do metalloids share with nonmetals

Physics
2 answers:
anzhelika [568]4 years ago
8 0
If your choices are :
Both are brittle.
Both are shiny.
Both have low melting points.
Both are very conductive

Then the answer is Both are brittle.
Naya [18.7K]4 years ago
6 0

Answer: b. both can react to form acidic compounds.

Explanation: bc nonmetals can form acidic compounds and metalloids have both properties of nonmetals and metals.

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A low orbit satellite at 100 km altitude had a camera that resolved a car location to within 0.3 meter. Find the minimum diamete
NeX [460]

Answer:

Minimum diameter of the camera lens is 22.4 cm

The focal length of the camera's lens is 300cm

Explanation:

y = Resolve distance = 0.3 m

h = Height of satellite = 100 km

λ = Wavelength = 550 nm

Angular resolution

tan\theta\approx \theta =\frac{y}{h}\\\Rightarrow \theta=\frac{0.3}{100\times 10^3}=3\times 10^{-6}

From Rayleigh criteria

sin\theta=1.22\frac{\lambda}{D}\\\Rightarrow D=1.22\frac{\lambda}{sin\theta}\\\Rightarrow D=1.22\frac{550\times 10^{-9}}{sin3\times 10^{-6}}=0.2236\ m=22.4\ cm

Minimum diameter of the camera lens is 22.4 cm

Relation between resolvable feature, focal length and angular resolution

d=f\Delta \theta\\\Rightarrow f=\frac{d}{\Delta \theta}\\\Rightarrow f=\frac{9\times 10^{-6}}{3\times 10^{-6}}=3\ m=300\ cm

The focal length of the camera's lens is 300cm

3 0
3 years ago
Why sky appear blue ​
NikAS [45]
Thus, as sunlight of all colors passes through air, the blue part causes charged particles to oscillate faster than does the red part. ... More of the sunlight entering the atmosphere is blue than violet, however, and our eyes are somewhat more sensitive to blue light than to violet light, so the sky appears blue.Apr 7, 2003
5 0
3 years ago
During the first 5 seconds after a ball is dropped from rest, how far will it fall?
agasfer [191]
The answer is 125metre
5 0
3 years ago
The temperature of an object is a measure of the average potential energy of the molecules in the object.
pav-90 [236]

Answer:

false

Explanation:

the temperature of an object is a measure of the average KINETIC ENERGY of the molecules in the object (not potential energy)

3 0
3 years ago
Coherent light with wavelength 608 nm passes through two very narrow slits, and the interference pattern is observed on a screen
Kipish [7]

Answer:

1.22 \mu m

Explanation:

In the double-slit interference, light passes through a double slit and produce a pattern of alternating bright and dark fringes on a distant screen. This pattern is due to the combined effect of the diffraction of each slit + the interference of the light coming from the two slits.

The condition to observe a maximum (bright fringe), so costructive interference, in the distant screen, is:

y=\frac{m\lambda D}{d}

where:

y is the distance of the m-th maximum from the central fringe

\lambda is the wavelength of the light used

D is the distance of the screen from the slits

d is the separation between the slits

In this problem, we know that:

\lambda=608 nm=608\cdot 10^{-9}m is the wavelength of light used

D=3.00 m is the distance of the screen

y=4.84 mm = 4.84\cdot 10^{-3} m is the distance of the first maximum (first-order bright fringe) from the central pattern, so when

m = 1

Solving for d, we find the separation of the slits:

d=\frac{m\lambda D}{y}=\frac{(1)(608\cdot 10^{-9})(3.00)}{4.84\cdot 10^{-3}}=3.77\cdot 10^{-4} m

The first dark fringe on the screen instead is given by the formula

y'=\frac{(\frac{\lambda'}{2})D}{d}

where

\lambda' is the wavelength of the new light

Here we want the first dark fringe of the new light to be coincident to the first bright fringe of the previous light, so

y=4.84\cdot 10^{-3}m

Therefore, solving for \lambda',

\lambda'=\frac{2y'd}{D}=\frac{2(4.84\cdot 10^{-3})(3.77\cdot 10^{-4})}{3.00}=1.22\cdot 10^{-6} m = 1.22 \mu m

4 0
3 years ago
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