U=10 m/s
v=30 m/s
t=6 sec
therefore, a=(v-u)/t
=(30-10)/6
=(10/3) ms^-2
now, displacement=ut+0.5*a*t^2
=60+ 0.5*(10/3)*36
=120 m
And you can solve it in another way:
v^2=u^2+2as
or, s=(v^2-u^2)/2a
=(900-100)/6.6666666.......
=120 m
Bottom of the water tower
Explanation:
When holes are drilled through the wall of a water tower, water will spurt out the greatest horizontal distance from the hole closest to the bottom of the water tower.
This is because the near the bottom of the tower is the greatest compared to other parts of the tower.
- The pressure increases with depth.
- As the depth of water increases, the column of water above exerts more pressure on the one below.
- Therefore, water will spurt out more from the bottom of the tower compared to the top of the tower.
Learn more:
Pressure brainly.com/question/4868239
#learnwithBrainly
ion:
h t t p s : / / w w w . y o u t u b e . c o m / w a t c h ? v = x a a z U g E K u V A
this is the video that explains it
Answer:
100 m/s²
Explanation:
50 N / 500 g = 50 N / 0.500 kg = 100 m/s²
