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zepelin [54]
3 years ago
10

Three kids are riding on a snow sled traveling horizontally without friction at 19.8 m/s. The masses of Kid A, B, and C are 42.8

kg, 31.5 kg, and 25.9 kg, respectively.
What is the new velocity of the sled if Kid A jumps off vertically from the sled? (Kid A velocity = 0)
Physics
1 answer:
larisa86 [58]3 years ago
4 0

Answer:

34.6 m/s

Explanation:

Considering the law of conservation of linear momentum, the sum of initial and final momentum are equal. Momentum, p is given by mv where m is the mass of object and v is the velocity of the object. For this question

M_iv_i=M_fv_f

where subscripts I and f represent initial and final

The initial mass compose of all the three kids but the final mass excludes kid A

Substituting 19.8 m/s for initial velocity and the other masses as given then

the initial mass is 42.8+31.5+25.9=100.2 Kg

Final mass is 31.5+25.9=57.4 Kg

100.2*19.8=57.4v_f\\v_f=\frac {100.2*19.8}{57.4}=34.56376307\ m/s\approx 34.6\ m/s

Therefore, the new velocity is 34.6 m/s

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Which response is the least effective when confronted with trying drugs or alcohol? "I'd rather be in control of what I do."
SVEN [57.7K]

Answer:

The least effective answer would be "It's okay to lose control every once in a while."

Explanation:

This answer would make it seem like you are either already on drugs or you are willing to try them, which i assume in this case, you are not.

6 0
3 years ago
An object is thrown upward from the top of a 160 foot building with an initial velocity of 48 feet per second. The height h of t
inn [45]

Answer:

t=5s

Explanation:

From free falling objects we know that height is equal to:

h=h_{o}+v_{oy}t+\frac{1}{2}gt^{2}

From the exercise we know that

h_{o}=160ft\\v_{oy}=48ft/s\\g=-32 ft/s^{2}

Being said that, we can calculate how long would it take to the object to hit the ground knowing that the height at that point is 0

0=160ft+(48ft/s)t-\frac{1}{2}(32ft/s^2)t^2

Solving the quadratic formula we got that

t=\frac{-b±\sqrt{b^{2}-4ac}}{2a}

a=-16\\b=48\\c=160

t=-2s or t=5s

Since time can not be negative the logical answer is <u><em>t=5s</em></u>

So, the object hit the ground at 5s

6 0
3 years ago
Read 2 more answers
If a box is pulled straight across the floor at a constant speed and it is pulled with a horizontal force of 48 N., what is the
Dima020 [189]

If its speed is constant and it's moving in a straight line, THAT's "constant, uniform motion".  That can only happen when there's NO net force on the object.  

So besides the 48 N forward that the puller is giving it, there must be friction with the floor, or mosquitoes all over it trying to fly backwards, or somebody crouched down behind it pulling it backwards, or some other kinds of things going on, that all add up to 48 N BACKWARDS.

Somehow, the NET force on the box has to be <em>zero, </em>because of the way it's moving.

7 0
3 years ago
You have seen that two objects with opposite charges attract each other, and two objects with the same charge repel each other.
Vesna [10]

Answer:

it should attract.........

6 0
3 years ago
A 2.0-kg block sliding on a rough surface is attached to one end of a horizontal spring (k = 200 N/m) which has its other end fi
earnstyle [38]

Answer:

The speed is 3.87 m/s

Explanation:

The total work is equal to the change to kinetic energy:

Wtotal = ΔEk

Wspring + Wfriction = Ekf - Eki

Eki = 0

-(\frac{1}{2} kd^{2} )-(fk*m*g*d^{2} )=\frac{1}{2} m(v^{2} -v_{i} ^{2} )

Where

k = 200 N/m

d = 10 cm = 0.1 m

fk = 0.15

m = 2 kg

g = 9.8 m/s²

vi = 4 m/s

Replacing and clearing v:

-(\frac{1}{2} *200*0.1^{2} )-(0.15*2*9.8*0.1^{2} )=\frac{1}{2} *2*(v^{2} -4^{2} )\\-1-0.0294=v^{2}  -16\\v=\sqrt{-1-0.0294+16} =3.87m/s

3 0
3 years ago
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