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zepelin [54]
3 years ago
10

Three kids are riding on a snow sled traveling horizontally without friction at 19.8 m/s. The masses of Kid A, B, and C are 42.8

kg, 31.5 kg, and 25.9 kg, respectively.
What is the new velocity of the sled if Kid A jumps off vertically from the sled? (Kid A velocity = 0)
Physics
1 answer:
larisa86 [58]3 years ago
4 0

Answer:

34.6 m/s

Explanation:

Considering the law of conservation of linear momentum, the sum of initial and final momentum are equal. Momentum, p is given by mv where m is the mass of object and v is the velocity of the object. For this question

M_iv_i=M_fv_f

where subscripts I and f represent initial and final

The initial mass compose of all the three kids but the final mass excludes kid A

Substituting 19.8 m/s for initial velocity and the other masses as given then

the initial mass is 42.8+31.5+25.9=100.2 Kg

Final mass is 31.5+25.9=57.4 Kg

100.2*19.8=57.4v_f\\v_f=\frac {100.2*19.8}{57.4}=34.56376307\ m/s\approx 34.6\ m/s

Therefore, the new velocity is 34.6 m/s

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Answer:

vₓ = 20 m/s,    v_{y}  = -15 m / s

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This is a conservation of moment problem, since it is a vector quantity we can work each axis independently

The system is formed by the two drones, so the forces during the crash are internal and the moment is conserved

X axis

Initial moment. Before the crash

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Final moment. After the crash

       p_{fx} = (m₁ + m₂) vₓ

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      m₁ v₀ₓ + m₂ v₀ₓ = (m₁ + m₂) vₓ

       vₓ = (m₁ + m₂) v₀ₓ / (m₁ + m₂)

       vₓ = v₀ₓ  = 20 m/s

Y Axis

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         p_{oy} = p_{fy}

the drom rises and when it falls it has the same speed because there is no friction    v_{oy} = -60 m/s          

 

           m₁ v_{oy} = (m₁ + m₂) v_{y}

            v_{y} = m₁ / (m₁ + m₂) v_{oy}

            v_{y}  = 1/4    60

            v_{y}  = -15 m / s

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