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lianna [129]
3 years ago
15

The concentration of glucose inside a cell is 0.12 mM. Outside the cell the concentration of glucose is 12.9 mM. Calculate the c

hange in Gibbs free energy for the transport of 1.50 moles of glucose into the cell at 37°C.
Chemistry
1 answer:
Alenkasestr [34]3 years ago
7 0

Answer:

The value of he change in Gibbs free energy ΔG = - 18.083 KJ

Explanation:

Given data

The concentration of glucose inside a cell is (P) = 0.12 m M

The concentration of glucose outside a cell is (R) = 12.9 m M

No. of  moles = 1.5 moles

The change in Gibbs free energy

ΔG = RT ㏑\frac{P}{R}

ΔG = 8.314 × 310 ㏑\frac{0.12}{12.9}

ΔG = - 12.055 \frac{J}{mole}

Since No. of  moles = 1.5 moles

Therefore

ΔG = - 12.055 × 1.5

ΔG = - 18.083 KJ

This the value of he change in Gibbs free energy.

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VLD [36.1K]

the formula  of the compound that  is formed  between  chlorine and calcium  is CaCl2


explanation

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Ionic compound   is formed when metal  loses electrons to form cation ( a  positively charged ion)  while  non metal  gains electrons  to  form anion (  a  negatively  charged ion)

An ionic compound is formed when calcium   metal(Ca) loses two electron to form   Ca2+ cation ,  while   2 chlorine atom  gain  one electron each to form cl- anions.


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How will you known that you have reached the equivalence point when titrating the NaOH solution with HCl?
Nitella [24]

Answer:

When the solution (with phenolphthalein) changes to colorless

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6 0
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In the laboratory, a quantity of I2 was reacted with excess H2 to give 1.26 moles of HI. It is also known that the percent yield
Anon25 [30]

Answer:

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Explanation:

Hello,

This question requires us to calculate the theoretical yield of I₂ or number of moles that reacted.

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Answer:

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