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cupoosta [38]
3 years ago
14

where 1s, 2s, and 2p are the occupied subshells, and the superscript "2" is the number of electrons in each of these subshells.

Use the rules for determining electron configurations to write the electron configuration for Ca. Express your answer in complete form in order of orbital filling. For example, 1s22s2 should be entered as 1s^22s^2.
Chemistry
1 answer:
SOVA2 [1]3 years ago
8 0

Answer: 1s^22s^22p^63s^23p^64s^2

Explanation:

Electronic configuration represents the total number of electrons that a neutral element contains. We add all the superscripts to know the number of electrons in an atom.

The electrons are filled according to Afbau's rule in order of increasing energies where orbital with higher value of (n+l) has higher energy as compared to orbital having lower (n+l) value. Thus the electronic configuration for calcium with atomic number of 20 and hence containing 20 electrons is :

Ca:20:1s^22s^22p^63s^23p^64s^2

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El volumen del aire en los pulmones de una persona es de 615 ml aproximadamente, a una presión de 760 mm Hg. La inhalación ocurr
Ann [662]

The volume of air in a person's lungs is about 615 ml, at a pressure of 760 mm Hg. Inhalation occurs when the pressure in the lungs drops to 752 mm Hg. To what volume do the lungs expand?

Answer:

621.5mL

Explanation:

Given parameters:

Initial volume  = 615mL

Initial pressure  = 760mmHg

Final pressure  = 752mmHg

Unknown;

Final volume  = ?

Solution:

To solve this problem, we simply apply Boyle's law.

"the volume of a fixed mass of a gas varies inversely as the pressure changes if the temperature is constant".

    Mathematically;

              P₁V₁  = P₂V₂

P and V are the pressure

1 and 2 are the initial and final states

 Now insert the parameters and start;

               760 x 615  = 752 x V₂

                   V₂ = 621.5mL

6 0
3 years ago
The pOH of a solution is 9.21. Calculate the hydrogen ion concentration of the solution. Be sure to report your answer to the co
11Alexandr11 [23.1K]

Answer:

[OH-] = 6.17 *10^-10

Explanation:

Step 1: Data given

pOH = 9.21

Step 2: Calculate [OH-]

pOH = -log [OH-] = 9.21

[OH-] = 10^-9.21

[OH-] = 6.17 *10^-10

Step 3: Check if it's correct

pOH + pH = 14

[H+]*[OH-] = 10^-14

pH = 14 - 9.21 = 4.79

[H+] = 10^-4.79

[H+] = 1.62 *10^-5

6.17 * 10^-10 * 1.62 * 10^-5 = 1* 10^-14

3 0
3 years ago
Atomic mass protons column electrons atomic number neutrons row 11 12 23
zysi [14]
A) Mass Number B) Protons and Electrons C) (I think group but I'm not 100% sure on this...) D) 12 (To work out the number of neutrons you do MASS number - ATOMIC number aka the number of protons so in this case you'd do 23-11=12) Hope this helps
3 0
4 years ago
I need help with number 13!
Anvisha [2.4K]
Try convection currents
8 0
3 years ago
Chemical Reactions Unit Test
dusya [7]

The right side of the equation yields 3CO₂+6H₂O molecules if the 2 in front of 2O is changed to a 3.

The correct option is A.

<h3>What are molecules ?</h3>

The smallest identifiable unit into which a pure substance can be divided while still retaining its composition and chemical properties is called a molecule.

<h3>Briefing:</h3>

Given the chemical equation expressed as:

CH₄+2O₂ → CO₂ + 2H₂O

According to the equation, 1 mole of methane and 2 moles of oxygen combine to create 1 mole of carbon dioxide and 2 moles of water.

The right equation will be written as: If 3 moles of oxygen are used in place of the original amount of moles of oxygen.

3CH₄+2(3O₂) → 3CO₂ + 6H₂O

This shows that the right side of the equation will result in 3CO₂+6H₂O if the 2 in front of 2O is changed to a 3.

To know more about Molecules visit:

brainly.com/question/19556990

#SPJ13

The complete question is -

Use the equation to answer the question.

CH₄+2O₂ → CO₂ + 2H₂O

If you change the 2 in front of 2O₂ to a 3, what will be the change in the results on the right side of the equation?

A- There are now 3CO₂+6H₂O. molecules.

B- There is an extra O₂ molecule left over.

C- Nothing changes in the equation.

D- There are now 3H₂O molecules.

3 0
1 year ago
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