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Lemur [1.5K]
3 years ago
12

Ranging from 0 to 14, a pH value indicates how acidic or basic a solution is. Which of these pH values would be a strong acid? *

Chemistry
2 answers:
NemiM [27]3 years ago
7 0

Answer:

its 2 because the middle one is 7 which is neutral hope that helps you

Eduardwww [97]3 years ago
4 0

Answer:

13 aaaàaàaaaaaaaaaßaaaaasssss

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Give 3 examples of solutions, suspensions and colloids..
Vlad [161]
  • <u>Some examples of solutions</u><u>"</u><u>:</u><u>"</u><u> are salt water, rubbing alcohol, and sugar dissolved in water.</u>

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5 0
2 years ago
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What kind of chemical change do you think occurs when a banana peel turns brown in the open air?
Alisiya [41]
Rotting, and ageing. The banana peel ages faster in open air, and therefor begins to rot. Brow peels don't mean that the banana is rotted, however, it is a sign that it may begin to rot soon.
6 0
3 years ago
Carbon has an atomic number of 6, but the following orbital notation for carbon is incorrect. Explain the error in terms of the
a_sh-v [17]

Carbon:

1s is filled. 2s is filled. 2p is shown to contain two electrons in one orbital and no electrons in the other two orbitals.

8 0
3 years ago
A piece of magnesium is in the shape of a cylinder with a height of 6.62 cm and a diameter of 2.34 cm. If the magnesium sample h
frez [133]

Answer:

0.600 g/cm³

Explanation:

Step 1: Given data

  • Height of the cylinder (h): 6.62 cm
  • Diameter of the cylinder (d): 2.34 cm
  • Mass of the cylinder (m): 17.1 g

Step 2: Calculate the volume of the cylinder

First, we have to determine the radius, which is half of the diameter.

r = d/2 = 2.34 cm/2 = 1.17 cm

Then, we use the formula for the volume of the cylinder.

V= π × r² × h

V= π × (1.17 cm)² × 6.62 cm

V = 28.5 cm³

Step 3: Calculate the density (ρ) of the sample

The density is equal to the mass divided by the volume.

ρ = m/V

ρ = 17.1 g/28.5 cm³

ρ = 0.600 g/cm³

8 0
2 years ago
For the gas phase decomposition of t-butyl propionate,C2H5COOC(CH3)3 (CH3)2C=CH2 + C2H5COOHthe rate constant at 540 K is 8.90×10
kvv77 [185]

Answer:

The activation energy is 164.02 kJ/mol

Explanation:

Log (k2/k1) = Ea/2.303R × [1/T1 - 1/T2]

k1 = 8.9×10^-4 s^-1

k2 = 9.83×10^-3 s^-1

R = 8.314 J/mol.K

T1 = 540 K

T2 = 578 K

Log (9.83×10^-3/8.9×10^-4) = Ea/2.303×8.314 × [1/540 - 1/578]

1.043 = 6.359×10^-6Ea

Ea = 1.043/6.359×10^-6 = 164020 J/mol = 164020/1000 = 164.02 kJ/mol

6 0
3 years ago
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