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EastWind [94]
3 years ago
12

Which of the following is a potential explanation to resolve the Fermi paradox?

Physics
1 answer:
aksik [14]3 years ago
8 0
Haiagakavsusbwosvahaoabhsosvsnajsksbzjd sos Kansas
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Common transparent tape becomes charged when pulled from a dispenser. If one piece is placed above another, the repulsice force
Dmitriy789 [7]

Answer:

Q = 1.095 x 10^-9 C

Let the force experienced by the top piece of tape be F

F = kQ²/r²

r = distance between the two pieces tape = 1.00cm = 1.00 x 10^ -2 m

1/4(pi)*Eo = k = 8.99 x 10^9 Nm²/C²

The electric force of repulsion between the two charges and the weight of the top piece of tape are equal so

F = kQ²/r² = mg

Where m is the mass of the top piece of tape and g is the acceleration due to gravity

On re-arranging the equation above,

Q² = mgr²/k

Q² = ((11.0 x 10^-6) x 9.8 x (1.00x10^-2)²)/(8.99 x 10^9)

Q = 1.095x10^-9 C

Explanation:

The charge Q on both pieces of tape are equal and both act with a force of repulsion on each other.

The force of repulsion between both tapes pushes the top piece of tape upwards. The weight of the top piece of tape acts vertically downward. Since the top tape is in a position of equilibrium, the two forces acting on the top piece of tape must be equal to each other. This assumption is backed up by newton's first law of motion which states that the summation of all forces acting on a body at rest must be equal to zero. That is

Fe (electric force) - Fg (gravitational force) = 0

Fe = Fg

kQ²/r² = mg

On substituting the respective values for all variables except Q and rearranging the equation Q = 1.09 x 10^-9

6 0
4 years ago
A 4-kilogram ball moving at 8 m/sec to the right collides with a 1-kilogram ball at rest. After the collision,
elena-14-01-66 [18.8K]
Conservation of momentum: total momentum before = total momentum after

Momentum = mass x velocity

So before the collision:
4kg x 8m/s = 32
1kg x 0m/s = 0
32+0=32

Therefore after the collision
4kg x 4.8m/s = 19.2
1kg x βm/s = β
19.2 + β = 32

Therefore β = 12.8 m/s
4 0
4 years ago
Find the magnitude of the emf induced in the rod when it is moving toward the right with a speed 7.50 m/s.
Flauer [41]

Answer:

3 volts

Explanation:

It is given that,

Magnetic field, B = 0.8 T

Length of a conducting rod, l = 50 cm = 0.5 m

Velocity of the conducting rod, v = 7.5 m/s

We need to find the magnitude of the emf induced in the rod when it is moving toward the right. When a rod is moved in a magnetic field, an emf is induced in it and it is given by :

\epsilon=Blv

Putting all the values,

\epsilon=0.8\times 0.5\times 7.5\\\\\epsilon=3\ V

So, the magnitude of the emf induced in the rod is 3 volts.

6 0
3 years ago
According to the text, how do small animals likemicerats,
Lesechka [4]

Answer:

According to the text you have given above,

Pigeons probably eat the plants from people's gardens.

Mice and Rats get food from the trash people.

(I guess this answer will help you :-)

4 0
4 years ago
Newtons third law is called law of action and reaction?
TiliK225 [7]

Answer:

His third law states that for every action (force) in nature there is an equal and opposite reaction. In other words, if object A exerts a force on object B, then object B also exerts an equal and opposite force on object A. ... In reaction, a thrusting force is produced in the opposite direction.

Explanation:

7 0
3 years ago
Read 2 more answers
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