A large ball of gas that is held together by gravity and that has a core so hot that

3. A large passenger ship required a force of 1,600,000 N to move 2000 m. How much work is done on the ship?

Dovator [93]

Answer:

3,200,000,000 J

Explanation:

Work is defined as the amount of energy transferred as an object is moved a certain distance with a certain force. Mathematically, we express this with the equation

$W=Fs$

where W is work (measured in joules), F is the force applied (in Newtons), and s is the distance, also called the displacement (in meters).

Here, we have F = 1,600,000 N and s = 2000 m, so our work will be

$W=1.600.000(2.000)=3.200.000.000$ J

7 0

3 years ago

the density of atmosphere (measured in kilograms/meter3) on a certain planet is found to decrease as altitude increases (as meas

statuscvo [17]

The type of relationship between atmospheric density and altitude is therefore inverse relationship. This means an increase in either will decrease the other factor. Density is mass per unit volume, it is difficult to calculate with only altitude 1,291 kilometers given. Else, we could also use temperature and pressure to solve density but they are not provided.

5 0

3 years ago

Read 2 more answers

Calculate the work done (in J) by a 90.0 kg man who pushes a crate 4.25 m up along a ramp that makes an angle of 20.0° with the

Mrrafil [7]

Answer:

W = 3.4x0³ J.

Explanation:

The work done by the man is given by the following equation:

$W = F_{t}\cdot d$ (1)

where W: is the work, Ft is the total force and d: is the displacement = 4.25 m.

We need to find first the total force Ft, which is:

$Ft = Fm + W$

where Fm: is the force exerted by the man = 535 N, W: is the weight = m*g*sin(θ), m: is the mass of the man, g: is the gravitational acceleration = 9.81 m/s², and θ: is the angle = 20.0°.

$F_{t} = Fm + W = 500 N + 90.0 kg*9.81 m/s^{2} * sin(20.0) = 802.0 N$

Hence, the work is:

$W = 802.0 N \cdot 4.25 m = 3.4 \cdot 10 ^{3} J$

Therefore, the work done by the man is 3.4x10³ J.

I hope it helps you!

8 0

3 years ago

Study the concentration amount shown on the juice label. Then answer the question. If you had 100 mL of juice, how many millilit

umka21 [38]

The answer is 25 ml for this question

8 0

4 years ago

Two particles, one with charge − 3.77 μC −3.77 μC and one with charge 4.39 μC, 4.39 μC, are 4.34 cm 4.34 cm apart. What is the m

Fudgin [204]

Answer:

the magnitude of the force that one particle exerts on the other is 79.08 N

Explanation:

given information:

q₁ = 3.77 μC = -3.77 x 10⁻⁶ C

q₂ = 4.39 μC = 4.39 x 10⁻⁶ C

r = 4.34 cm = 4.34 x 10⁻² m

What is the magnitude of the force that one particle exerts on the other?

lFl = kq₁q₂/r²

= (9 x 10⁹) (3.77 x 10⁻⁶) (4.39 x 10⁻⁶)/(4.34 x 10⁻²)²

= 79.08 N

8 0

3 years ago