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Ira Lisetskai [31]
4 years ago
13

Suppose a water tank in the shape of a right circular cylinder is thirty feet high and eight feet in diameter. a) How much sheet

metal was used in its construction of the whole water tank? Round to the nearest hundredth.
Mathematics
1 answer:
Zanzabum4 years ago
5 0

Answer:

755.98 ft^2

Step-by-step explanation:

Height of the Cylinder= 30 feet

Diameter = 8 feet

Radius= Diameter/2 = 8/2 = 4 feet

The Amount of Metal Sheet used in constructing the tank is the Total  Surface Area of the Tank.

Total Surface Area of a Cylinder =

=2\pi r(r+h)\\=2*\pi*4(4+30)\\=8*\pi*30=\\=240\pi\\=755.98 ft^2

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\cdot \: \mathsf{x^{2} + \dfrac{2}{3} x + \dfrac{4}{9}} \\ \\ \\ \mathsf{\sqrt{x^{2}} \times \sqrt{\dfrac{4}{9}} \times 2 =} \\ \\ \\ \mathsf{x \times \dfrac{2}{3} \times 2 =} \\ \\ \\ \mathsf{\dfrac{4}{3} x \rightarrow it \: is \: not \: a \: perfect \: square \: trinomial}

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\cdot \: \mathsf{x^{2} + \dfrac{2}{3} x + \dfrac{1}{9} + 4 = x^{2} + \dfrac{2}{3} x + \dfrac{37}{9}} \\ \\ \\ \mathsf{\sqrt{x^{2}} \times \sqrt{\dfrac{37}{9}} \times 2 =} \\ \\ \\ \mathsf{x \times \dfrac{\sqrt{37}}{3} \times 2 =} \\ \\ \\ \mathsf{\dfrac{2\sqrt{37}}{3} x \rightarrow it \: is \: not \: a \: perfect \: square \: trinomial}

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