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barxatty [35]
4 years ago
14

When do plants use the process of cellular respiration

Chemistry
1 answer:
d1i1m1o1n [39]4 years ago
8 0

Answer:

So the answer is every day

Explanation:

Plants respire at all times of the day and night because their cells need a constant energy source to stay alive.

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Which of the following steps correctly converts 1.25 moles of fluorine to an equivalent mass of fluorine in grams? (5 points)
steposvetlana [31]

Explanation:

Given the amount of fluorine is ---- 1.25 mol.

What is the mass of given fluorine in grams?

Since

Number of moles =\frac{given mass of the substance}{its molecular mass}

To get the mass of the substance in grams, multiply the given number of moles with the molecular mass of the substance.

Hence, among the given options, the correct answer is the last option that is

Multiply the atomic mass of fluorine by 1.25.

5 0
3 years ago
What situation would not encourage competition ?
just olya [345]

Answer:

2

Explanation:

it leads to more food which leads to a  decrease in competition

hope this helps :)

6 0
3 years ago
Match the term to the correct definition.
nexus9112 [7]
1 is A 2 is B
Primary Consumers are Herbivores (vegetarians) and Secondary Consumers are Carnivores (meat eaters)
3 0
3 years ago
Read 2 more answers
Which weather condition is NOT associated with warm fronts??
slavikrds [6]

Answer:

A Winter storm usually does not come with a warm fronthey warm front.

Explanation:

When the front passes over an area it means to change in the weather. Many. Many friends cause weather events such as rain thunderstorms gusty winds tornadoes and hurricanes.

5 0
2 years ago
A student dissolved 5.00 g of Co(NO3)2 in enough water to make 100. mL of stock solution. He took 4.00 mL of the stock solution
Marianna [84]

Answer:

0.136g

Explanation:

A student dissolved 5.00 g of Co(NO3)2 in enough water to make 100. mL of stock solution. He took 4.00 mL of the stock solution and then diluted it with water to give 275. mL of a final solution. How many grams of NO3- ion are there in the final solution?

Co(NO_3)_2(aq)\rightarrow Co^{2+}(aq)+2NO_3^{-}(aq)

Initial mole of Co(NO3)2  =\frac{mass}{molar mass}

=\frac{5.00}{182.94} \\\\=0.02733mol

Mole of Co(NO3)2 in final solution

=\frac{4.00}{100}\times 0.02733\\\\=0.04\times 0.02733\\\\= 0.001093mol

Mole of  NO3- in final solution = 2 x Mole of Co(NO3)2

=2\times 0.001093\\\\=0.002186mol

Mass of  NO3- in final solution is mole x Molar mass of NO3

=0.002186\times62.01\\\\=0.136g

6 0
3 years ago
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