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Anestetic [448]
2 years ago
15

Which of the following vary for isotopes of atoms of the same element?

Chemistry
2 answers:
cupoosta [38]2 years ago
7 0

Answer:

The answer is B. Atomic Mass

Mila [183]2 years ago
5 0
Atomic mass because “Different isotopes of the same element have the same atomic number. They have the same number of protons.” and it cant be electrons since they’re equal to protons and in isotopes only neutrons are differnet. “Isotopes are atoms with different atomic masses which have the same atomic number.”
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There are two types of physical changes and chemical reactions- endothermic and exothermic. On the diagram below, which picture
Agata [3.3K]

Answer:

it is b because its releases heat in to all directions and not b because it staying inside and not releasing anything :)

Explanation:

6 0
3 years ago
Read 2 more answers
The density of water is 1.0gcm3 at 4∘C. What is the mass of 15mL of water at this temperature?
muminat

Answer:

15 gram

Explanation:

in one liter

=1000ml = 1000 cm3

so 15 ml = 15 cm3

15 cm3 = 15 gram

6 0
3 years ago
In a particular redox reaction, no2– is oxidized to no3– and cu2 is reduced to cu . Complete and balance the equation for this r
lianna [129]

Reduction half reaction: Cu²⁺(aq) + 2e⁻ → Cu⁰(s).


Oxidation half reaction: NO₂⁻(aq) + H₂O(l) → NO₃⁻(aq) + 2H⁺(aq) + 2e⁻.  

Balanced chemical reaction:

Cu²⁺(aq) + NO₂⁻(aq) + H₂O(l) → Cu(s) + NO₃⁻(aq) + 2H⁺(aq).

Copper is reduced from oxidation number +2 (Cu²⁺) to oxidation number 0 (Cu) and nitrogen is oxidized from oxidation number +3 (in NO₂⁻) to oxidation number +5 (in NO₃⁻).


8 0
2 years ago
Read 2 more answers
A helium-filled balloon at 310.0 K and 1 atm, contains 0.05 g He, and has a volume of 1.21 L. It is placed in a freezer (T = 235
trapecia [35]

Answer : The value of \Delta E of the gas is 2.79 Joules.

Explanation :

First we have to calculate the moles of helium.

\text{Moles of helium}=\frac{\text{Mass of helium}}{\text{Molar mass of helium}}

Molar mass of helium = 4 g/mole

\text{Moles of helium}=\frac{0.05g}{4g/mole}=0.0125mole

Now we have to calculate the heat.

Formula used :

q=nc_p\Delta T\\\\q=nc_p(T_2-T_1)

where,

q = heat

n = number of moles of helium gas = 0.0125 mole

c_p = specific heat of helium = 20.8 J/mol.K

T_1 = initial temperature = 310.0 K

T_2 = final temperature = 235.0 K

Now put all the given values in the above formula, we get:

q=nc_p(T_2-T_1)

q=(0.0125mole)\times (20.8J/mol.K)\times (235.0-310.0)K

q=-19.5J

Now we have top calculate the work done.

Formula used :

w=-p\Delta V\\\\w=-p(V_2-V_1)

where,

w = work done

p = pressure of the gas = 1 atm

V_1 = initial volume = 1.21 L

V_2 = final volume = 0.99 L

Now put all the given values in the above formula, we get:

w=-p(V_2-V_1)

w=-(1atm)\times (0.99-1.21)L

w=0.22L.artm=0.22\times 101.3J=22.29J

conversion used : (1 L.atm = 101.3 J)

Now we  have to calculate the value of \Delta E of the gas.

\Delta E=q+w

\Delta E=(-19.5J)+22.29J

\Delta E=2.79J

Therefore, the value of \Delta E of the gas is 2.79 Joules.

3 0
3 years ago
Hey what's 10 & 11 y'all im dumb
lesya [120]

Answer:

10 is 2.89g/ml

11 in attachment

Explanation:

10. D=M/V

M=250G-120G=130G

V=75ML-30ML=45ML

D=130/45=2.89g/ml

3 0
2 years ago
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