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stich3 [128]
3 years ago
8

Which ones are the alternative exterior angles

Mathematics
2 answers:
lakkis [162]3 years ago
7 0

Answer:


Step-by-step explanation:

Angle pair 1 and 8


and


Angle pair 2 and 7

Anvisha [2.4K]3 years ago
4 0
It would be angle 1 and angle 8
Hope this helps!!❤️
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Look at the graph. Can u find the slope ? Help plsss
Trava [24]

Answer:

1/3

Step-by-step explanation:

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3 0
3 years ago
A plane traveling with the wind travels 900 miles in 5 hours. the return trip is against the wind and takes 9 hours. find the ra
Aneli [31]

Using the relation between velocity, distance and time, it is found that:

  • The rate of the plane in still air is of 140 mph.
  • The rate of the wind is of 40 mph.

<h3>What is the relation between velocity, distance and time?</h3>

Velocity is <u>distance divided by time</u>, that is:

v = \frac{d}{t}

A plane traveling with the wind travels 900 miles in 5 hours, hence:

v_a + v_w = \frac{900}{5}

v_a + v_w = 180

The return trip is against the wind and takes 9 hours, hence:

v_a - v_w = \frac{900}{9}

v_a - v_w = 100

From the first equation, we have that:

v_w = 180 - v_a{/tex]Replacing on the second:[tex]v_a - v_w = 100

v_a - 180 + v_a = 100

2v_a = 280

v_a = 140

[tex]v_w = 180 - 140 = 40{/tex]

Hence:

  • The rate of the plane in still air is of 140 mph.
  • The rate of the wind is of 40 mph.

More can be learned about the relation between velocity, distance and time at brainly.com/question/24316569

4 0
2 years ago
ANYONE GOOD AN ANNUITIES?
Anettt [7]
Given:
quarterly deposits of 2,000
8 percent compounded quarterly ⇒ 2% per quarter
4 quarters in 15 years = 60 quarters

Future Value = (1 + r) x P [{(1+r)^n - 1} / r]

FV = (1 + 0.02) x 2,000 [{(1 + 0.02)⁶⁰ - 1} / 0.02]

FV = 232, 665.14 Choice B.
3 0
3 years ago
How do I work this out
Iteru [2.4K]
If the track is 10km long, and X travels at 40 km/h, it will take 1 hour to do 4 laps. this means that car X will do one lap in 15 minutes. Y travels at 30 km/h, which means it will do 3 laps in 1 hour, meaning that car X will do 1 lap in 20 minutes.

X- 15, 30, 45, 60
Y-20, 40, 60


Therefore, after an hour, they will pass again.
5 0
4 years ago
3.16 SAT scores: SAT scores (out of 2400) are distributed normally with a mean of 1490 and a standard deviation of 295. Suppose
AURORKA [14]

Answer:

0.2333 = 23.33% probability this student's score will be at least 2100.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution, and conditional probability.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

SAT scores (out of 2400) are distributed normally with a mean of 1490 and a standard deviation of 295.

This means that \mu = 1490, \sigma = 295

In this question:

Event A: Student was recognized.

Event B: Student scored at least 2100.

Probability of a student being recognized:

Probability of scoring at least 1900, which is 1 subtracted by the pvalue of Z when X = 1900. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{1900 - 1490}{295}

Z = 1.39

Z = 1.39 has a pvalue of 0.9177

1 - 0.9177 = 0.0823

This means that P(A) = 0.0823

Probability of a student being recognized and scoring at least 2100:

Intersection between at least 1900 and at least 2100 is at least 2100, so this is 1 subtracted by the pvalue of Z when X = 2100.

Z = \frac{X - \mu}{\sigma}

Z = \frac{2100 - 1490}{295}

Z = 2.07

Z = 2.07 has a pvalue of 0.9808

This means that P(A \cap B) = 1 - 0.9808 = 0.0192

What is the probability this student's score will be at least 2100?

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.0192}{0.0823} = 0.2333

0.2333 = 23.33% probability this student's score will be at least 2100.

4 0
3 years ago
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