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r-ruslan [8.4K]
3 years ago
10

T.B., a 65-year-old woman, fell as she was leaving her home. She was unable to move her left leg and appeared to be inextreme pa

in when the paramedics transported her to a stretcher. She was later diagnosed with a fractured hip and sentto surgery, where a pin was inserted into the fractured bone. A bone scan indicated a decrease in bone density.Which anatomical structure was fractured?a. iliac crest of the coxal boneb. ischial tuberosity of the hip bonec. greater trochanter of the femurd. neck of the femur
Biology
1 answer:
slamgirl [31]3 years ago
3 0

Answer:

The correct answer is C. <em>Greater throcanter of the femur.</em>

Explanation:

Hip fractures describe all those fractures that occur in the proximal extremity of the femur.

According to the location of the fracture in the extremity, it can affect the femoral head, the femoral neck, the trochanter of the femur or the area under the femur.

Most of the hip fractures occur in older people, mostly in women, and mainly, the causes of fractures are falls or missteps.

For the treatment, there are some surgery options, among other more conservatory. One of them is <u>hip pinning</u>, which is considered a good option for fractures that occur in the<u> greater and lesser part of the trochanter</u> in the femur bone.

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High-density lipoproteins (HDL) refer to macromolecular complexes made up of lipids and that have the function of transporting dietary lipids to the liver.

<h3>What are lipoproteins?</h3>

They are macromolecules whose function is to package insoluble lipids in the aqueous medium of plasma and transport them from the intestine and liver to peripheral tissues and, from these, return cholesterol to the liver for elimination from the body.

<h3>Characteristics of High Density Lipoproteins (HDL)</h3>

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  • They transport cholesterol from peripheral tissues to the liver, this is known as “Reverse Cholesterol Transport”.

Therefore, we can conclude that lipoproteins are macromolecules whose function is to transport lipid molecules from one organ to another in the aqueous medium of plasma.

Learn more about lipoproteins here: brainly.com/question/16170788

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2 years ago
How will the change in pH impact the functioning of cells? (Hint: Explain which biomolecules and what types of bonds in these bi
Effectus [21]

Answer:

A change in pH will cause many cellular processes to be disrupted because they affect the biomolecules (protein and nucleic acid) responsible for these processes.

Explanation:

pH refers to the degree of acidity or alkalinity. In a cell, the structures and processes that occur in them are impossible without the biomolecules, which are carbohydrate, protein, lipids and protein.

However, unfavorable conditions like a change in pH can cause the structure of some of these biomolecules to be affected. Proteins are made up of amino acids, which gives them their shape that is peculiar to their functioning. Also, nucleic acids such as DNA are composed of nucleotides responsible for their functioning.

A change in pH will cause the bonds of the protein to be disrupted, hence altering its shape and ultimately its functioning. Likewise, the hydrogen bonds in the DNA will be broken in the presence of a high pH causing the DNA to be dysfunctional.

When these biomolecules are affected, the vital functions that they perform in a cell, which is key to the cell's survival are disrupted) are likewise affected. Therefore, the cell is affected negatively.

8 0
3 years ago
Ozone depletion can have negative
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7 0
1 year ago
A bacterial sample has a cell density of 1.85 x106 CFU/mL. What plate dilution should yield a countable plate? Which two dilutio
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Answer:

Explanation:

Bacterial count in stock- 1.85x10^6 cfu/ml

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Take 100 uL or (0.1ml) from stock and add to 900ul (0.9ml) saline and mixed it- this makes 10^1dilution.

Now take 100ul from 10^1 dilution and add to next 900ul saline this is 10^2 dilution, similarly do upto 10^5 dilution.

Then take 100ul from 10^ 4 and 10^5 dilution seperately and plate on LB agar plate seperetely and count the colonies.

Cfu/ml formula= (No.of colonies x dilution factor)/0.1 ml

So suppose, 18 colonies formed on 10^4 dilution then total no. Of cells in stock will be 18x10^4/ 0.1= 18x10^5 cfu/ml.

If we dilute 10^4 or 10^5 that's leads to colony count of 18-19 colonies on 10^4 dilution while 2 colonies should come on plate of 10^5 dilution.

7 0
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Explanation:

5 0
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