I think its A. because there are nuclear fusion and nuclear fission
Answer;
294.13 amu
Solution;
-293nv is 293.10 amu and that of 295nv is 295.45 amu
293.05+295.2=588.25
588.25/2= 294.13 amu
an amu of 294.13 using significant figures
Answer:
8.73
Explanation:
when you are adding or subtracting numbers, the sigfig (significant figure) is based on how many numbers after the decimal. with this info, we can see that 15.67 has 2 sigfigs and 6.943 has 3 sigfigs. when you subtract normally, you would get 8.727, which has 3 sigfigs, so you would round the last 7 up to get 8.73 with 2 sigfigs!
also it is to 2 sigfigs because we know that we go by the least number of sigfigs. hope this helped!
V-?
p≈1g/mL (estimated density of solution)
w=0.02
m(Cli)=12 g
the mass of the solution is:
m=Vp
w=m(Cli)/m=m(Cli)/Vp
the volume of the solution is:
V=m(Cli)/(pw)
V=12g/(1g/mL*0.02)=600 mL
