1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Serhud [2]
3 years ago
5

Which of the following elements will lose electrons to form an ion

Chemistry
1 answer:
vampirchik [111]3 years ago
4 0

Answer:

Metals

Explanation:

Metallic elements are renowned for their ability to freely lose electrons to form ions.

This is because metals are electropositive in nature. When a substance is electropositive, it readily wants to lose electrons and form positive ions.

Non-metals prefers to gain electrons and are electronegative.

You might be interested in
Which are examples of dynamic equilibrium
sweet-ann [11.9K]

Answer:Dynamic Equilibrium Examples. Any reaction will be in dynamic equilibrium if it's reversible and the rates of the forward and reverse reactions are equal. For example, say that you prepare a solution that is saturated with an aqueous solution of NaCl.

Explanation:

8 0
3 years ago
Read 2 more answers
Juan observes a material in the rocks of a hilluan hammers off a piece and then examines the pieces with a hana tena He
Nata [24]

Answer:

I definitely think he mostly observed that it was clear in color.

Explanation:

5 0
3 years ago
A solution was prepared by mixing 0.5000 m hno2 with 0.380 m no2-. ka = 4.58 x 10-4. calculate the ph of the solution. show work
adell [148]

pH of buffer can be calculated as:

pH=pKa+log[salt]/[Acid]

As ka = 4.58 x 10-4

Concentration of [Salt] that is NO2(-1)=0.380M

Concentration of [Acid] that is HNO2=0.500M

So, pH= -log(4.58*10^-4)+log((0.380)/0.500))

=3.21

So pH of solution will be 3.21

7 0
3 years ago
Solid sodium azide (NaN3) produces solid sodium and nitrogen gas. How many grams of sodium azide are needed to yield a volume of
ch4aika [34]

Answer:

52.008 grams of sodium azide are needed to yield a volume of 26.5 L of nitrogen gas at a temperature of 295 K and a pressure of 1.10 atmospheres.

Explanation:

An ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law, an equation that relates the three variables if the amount of substance, number of moles n, remains constant and where R is the molar constant of the gases:

P*V = n*R*T

In this case, the balanced reaction is:

2 NaN₃ → 2 Na + 3 N₂

You know the following about N₂:

  • P= 1.10 atm
  • V= 26.5 L
  • n=?
  • R=0.082057 \frac{atm*L}{mol*K}
  • T= 295 K

Replacing in the equation for ideal gas:

1.10 atm* 26.5 L= n* 0.082057 \frac{atm*L}{mol*K}*295 K

Solving:

n=\frac{1.10 atm*26.5 L}{0.082057 \frac{atm*L}{mol*K} *295K}

n= 1.2 moles

Now, the following rule of three can be applied: if 3 moles of N₂ are produced by stoichiometry of the reaction from 2 moles of NaN₃, 1.2 moles of N₂ are produced from how many moles of NaN₃?

moles of NaN_{3}=\frac{1.2 molesofN_{2} *2 molesofNaN_{3} }{3 molesofN_{2} }

moles of NaN₃= 0.8

Since the molar mass of sodium azide is 65.01 g / mol, then one last rule of three applies: if 1 mol has 65.01 grams of NaN₃, 0.8 mol how much mass does it have?

mass of NaN_{3} =\frac{0.8 mol*65.01 grams}{1 mol}

mass of NaN₃=52.008 grams

<u><em>52.008 grams of sodium azide are needed to yield a volume of 26.5 L of nitrogen gas at a temperature of 295 K and a pressure of 1.10 atmospheres.</em></u>

6 0
3 years ago
Read 2 more answers
You perform a distillation to separate a mixture of propylbenzene and cyclohexane, and you obtain 2.9949 grams of cyclohexane (d
Romashka-Z-Leto [24]

Answer:

66.67%

Explanation:

From the given information:

mass of cyclohexane = 2.9949 grams

density of cyclohexane = 0.779 g/mL

Recall that:

Density = mass/volume

∴

Volume = mass/density

So, the volume of cyclohexane = 2.9949 g/ 0.779 g/mL

= 3.8445 mL

Also,

mass of propylbenzene = 1.6575 grams

density of propylbenzene = 0.862 g/mL

Volume of propylbenzene =  1.6575 g/ 0.862 g/mL

= 1.9229 mL

The volume % composition of cyclohexane from the mixture is:

= (\dfrac{v_{cyclohexane}}{v_{cyclohexane}+v_{propylbenzene}})\times 100

= (\dfrac{3.8445}{3.8445+1.9229})\times 100

= (\dfrac{3.8445}{5.7674})\times 100

= 66.67%

6 0
3 years ago
Other questions:
  • Which practice poses the greatest safety concern?
    8·2 answers
  • 1.Explore two more isotopes and how it is useful in our day to day life.
    13·1 answer
  • When calcium (Ca) is mixed with hydrochloric acid (HCl), a single replacement reaction occurs. What will be the product or produ
    11·2 answers
  • Approximate temperature of a .7 mold sample of a gas at 1.2 ATM and volume of .170 L
    10·1 answer
  • Predict ​the polarity of 6 real molecules. First, draw the molecules and any bond dipoles. Then draw any molecular dipoles. Expl
    9·1 answer
  • 2) Where is Earth, exactly? Use this image to find our location. Earth is
    15·1 answer
  • What are the terms for A, B, C?<br> C<br> А<br> В
    14·1 answer
  • Anybody who wants to ta lk can come to me.
    7·1 answer
  • During 5th period Dylan was a beast. She resisted the forces applied by 13 other students in her class all at once. Her 13 class
    7·1 answer
  • An increase in enzyme or substrate concentration will
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!