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neonofarm [45]
4 years ago
5

Balance the equation NH4OH + H3PO4 What Are the products of NH4OH + H3PO4

Chemistry
1 answer:
Troyanec [42]4 years ago
6 0

Answer:

3NH₄OH  +  H₃PO₄  → (NH₄)₃PO₄  +  3H₂O

Products are water and  ammonium phosphate

Explanation:

This is a neutralization between a weak base and a weak acid where the products are water and the correspondent salt.

Base:  NH₄OH  →  NH₄⁺  +  OH⁻

Acid :  H₃PO₄  →  3H⁺  +  PO₄⁻³

H⁺ bonds to OH⁻ to make H₂O → As we have 3 protons, we can make 3 moles of water, so there are needed 3 OH⁻.

Phosphate has -3 as oxidation state, then it needs 3 ammonium to form the salt.

The balanced equation is:

3NH₄OH  +  H₃PO₄  → (NH₄)₃PO₄  +  3H₂O

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Calculate the percent ionization of nitrous acid in a solution that is 0.230 M in nitrous acid. The acid dissociation constant o
djyliett [7]
Ok first, we have to create a balanced equation for the dissolution of nitrous acid.

HNO2 <-> H(+) + NO2(-)

Next, create an ICE table

           HNO2   <-->  H+        NO2-
[]i        0.230M          0M       0M
Δ[]      -x                   +x         +x
[]f        0.230-x          x           x

Then, using the concentration equation, you get

4.5x10^-4 = [H+][NO2-]/[HNO2]

4.5x10^-4 = x*x / .230 - x

However, because the Ka value for nitrous acid is lower than 10^-3, we can assume the amount it dissociates is negligable, 

assume 0.230-x ≈ 0.230

4.5x10^-4 = x^2/0.230

Then, we solve for x by first multiplying both sides by 0.230 and then taking the square root of both sides.

We get the final concentrations of [H+] and [NO2-] to be x, which equals 0.01M.

Then to find percent dissociation, you do final concentration/initial concentration.

0.01M/0.230M = .0434 or 

≈4.34% dissociation.
8 0
3 years ago
You place your hand on the thermos what type of transfer is taking place
AlexFokin [52]

Answer:

conduction

Explanation:

Conduction happens when 2 objects with different temperatures come in contact with each other. The heat transfers from the hotter object to the cooler object.Apr

4 0
3 years ago
Read 2 more answers
A large balloon contains 233 L of neon at 22.0C and 760. Torr. If the balloon ascends to an altitude where the temperature is -
shepuryov [24]

Answer: The volume in the balloon at the higher altitude is 260 L

Explanation:

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 760 torr

P_2 = final pressure of gas = 511 torr

V_1 = initial volume of gas = 233 L

V_2 = final volume of gas = ?

T_1 = initial temperature of gas = 22.0^0C=(22.0+273)K=295K

T_2 = final temperature of gas = -52.0^0C=(-52.0+273)K=221K

Now put all the given values in the above equation, we get:

\frac{760\times 233}{295}=\frac{511\times V_2}{221}

V_2=260L

The volume in the balloon at the higher altitude is 260 L

3 0
3 years ago
Question 5 (1 point)
Aleksandr-060686 [28]

Answer : The pressure it exert under these new conditions will be, 87 atm

Explanation :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 19 atm

P_2 = final pressure of gas = ?

V_1 = initial volume of gas = 100 L

V_2 = final volume of gas = 20 L

T_1 = initial temperature of gas = 25^oC=273+25=298K

T_2 = final temperature of gas = 0^oC=273+0=273K

Now put all the given values in the above equation, we get:

\frac{19atm\times 100L}{298K}=\frac{P_2\times 20L}{273K}

P_2=87atm

Therefore, the pressure it exert under these new conditions will be, 87 atm

5 0
3 years ago
As altitude increases, what is the trend in density of the air in the atmoshere
Finger [1]
The density will become less, this is because thing with less density float to the top when things with more density float to the bottom. It also becomes colder.
5 0
4 years ago
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