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Butoxors [25]
3 years ago
14

Why does x hexane dissolve readily in tetrachloromethane​

Chemistry
1 answer:
DedPeter [7]3 years ago
6 0

Answer:

because high intermolecular fotce

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Which substance has vibrating particles in fixed positions? Ca(S) or CaCl2 (aq)
OLga [1]

Ca(S) I looked it up



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3 years ago
What is the predominant intermolecular force between ibr molecules in liquid ibr?
jasenka [17]

Answer is: dispersion forces.

The London dispersion force is the weakest intermolecular force.

Dispersion force is also called an induced dipole-induced dipole attraction.

The London dispersion force (intermolecular force) is a temporary attractive force between molecules.

The dipole beetween iodine and bromine is weak.

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3 years ago
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When parallel light rays exit a concave lens,the light ray is?
ad-work [718]
When parallel rays exit a concave lens, the light rays are divergent.
The rays diverge or bend away from the axis it has been traveling upon entering the lens when it reaches the other side of the lens. These rays appear to have come from the same focal point before entering the concave lens. When these parallel rays are extended, it will be traced back to a single point of origin.
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A solution of sodium hydroxide was titrated against a solution of sulfuric acid. How many moles of sodium hydroxide would react
jeka57 [31]

Answer:

2 mole of Sodium hydroxide reacts with 1 mole of Sulfuric acid

Explanation:

Write down the equation in the beginning with reactants and products:

NaOH + H₂SO₄ → Na₂SO₄ + H₂0

Now try to balance it. Try with Na first:

2NaOH + H₂SO₄ → Na₂SO₄ + H₂0

Na atoms are balanced. There are 6 Oxygen atoms on the right and 5 on the left. Balance by increasing the H₂O moles:

2NaOH + H₂SO₄ → Na₂SO₄ + 2H₂0

Check if H atoms are also balanced. They are. That means our final reaction is:

2NaOH + H₂SO₄ → Na₂SO₄ + 2H₂0

2 Moles of NaOH reacts with 1 mole of H₂SO₄

5 0
3 years ago
A chemistry student is given 700. mL of a clear aqueous solution at 26.° C. He is told an unknown amount of a certain compound
Alex73 [517]

Answer:

The correct answer is - yes, 4.57 g of solute per 100 ml of solution

Explanation:

The correct answer is yes we can calculate the solubility of X in the water at 22.0°C. The salt will remain after the evaporate from the dissolved and cooled down at 26°C.

Then, the amount of solute dissolved in the 700 ml solution at 26°C is the weighed precipitate: 0.032 kg = 32 g.

Then solublity will be :

32. g solute / 700 ml solution = y / 100 ml solution

⇒ y = 32. g solute × 100 ml solution / 700 ml solution = 4.57 g.

Thus, the answer is 4.57 g of solute per 100 ml of solution.

5 0
2 years ago
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