Hydrogen peroxide mixed with vinegar makes peracetic acid, which is a toxic gas that irritates the skin and respiratory system
Answer:
Bioluminescence Imaging.
Explanation:
Bioluminescence is appealing as an approach for in vivo optical imaging in mammalian tissues because these tissues have low intrinsic bioluminescence; therefore, images can be generated with remarkably high signal-to-noise ratios. A variety of different bioluminescent systems have been identified in nature, each requiring a specific enzyme and substrate. Although the most commonly used bioluminescent reporter for research purposes has been luciferase from the North American firefly (Photinus pyralis; FLuc), useful luciferases have also been cloned from jellyfish (Aequorea), sea pansy (Renilla; RLuc), corals (Tenilla), click beetle (Pyrophorus plagiophthalamus), and several bacterial species (Vibrio fischeri, V. harveyi).
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The answer is Coal. Atmospheric pollution is least when geothermal electricity is used to produce electricity.
<u>Answer:</u> The moles of oxygen and carbon dioxide in air is
and
respectively
<u>Explanation:</u>
To calculate the number of moles, we use the equation:
![\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}](https://tex.z-dn.net/?f=%5Ctext%7BNumber%20of%20moles%7D%3D%5Cfrac%7B%5Ctext%7BGiven%20mass%7D%7D%7B%5Ctext%7BMolar%20mass%7D%7D)
Given mass of atmosphere = ![5.00\times 10^{18}kg=5.00\times 10^{21}g](https://tex.z-dn.net/?f=5.00%5Ctimes%2010%5E%7B18%7Dkg%3D5.00%5Ctimes%2010%5E%7B21%7Dg)
Average molar mass of atmosphere = 28.96 g/mol
Putting values in above equation, we get:
![\text{Moles of atmosphere}=\frac{5.00\times 10^{21}g}{28.96g/mol}=1.73\times 10^{20}mol](https://tex.z-dn.net/?f=%5Ctext%7BMoles%20of%20atmosphere%7D%3D%5Cfrac%7B5.00%5Ctimes%2010%5E%7B21%7Dg%7D%7B28.96g%2Fmol%7D%3D1.73%5Ctimes%2010%5E%7B20%7Dmol)
We know that:
Percent of oxygen in air = 21 %
Percent of carbon dioxide in air = 0.0415 %
Moles of oxygen in air = ![\frac{21}{100}\times 1.73\times 10^{20}=3.63\times 10^{19}mol](https://tex.z-dn.net/?f=%5Cfrac%7B21%7D%7B100%7D%5Ctimes%201.73%5Ctimes%2010%5E%7B20%7D%3D3.63%5Ctimes%2010%5E%7B19%7Dmol)
Moles of carbon dioxide in air = ![\frac{0.0415}{100}\times 1.73\times 10^{20}=7.18\times 10^{16}mol](https://tex.z-dn.net/?f=%5Cfrac%7B0.0415%7D%7B100%7D%5Ctimes%201.73%5Ctimes%2010%5E%7B20%7D%3D7.18%5Ctimes%2010%5E%7B16%7Dmol)
Hence, the moles of oxygen and carbon dioxide in air is
and
respectively