Answer:
It is a function Jonny!
Step-by-step explanation:
Hello! I would say to Jonny:
Jonny! A function is a relation between two sets, in which every element of the first set (domain) is assigned only one element of the second set (codomain).
If you have serveral elements of the first set with the same corresponding element of the second set it is correct to call that relation a function.
However, if you have an element of the first set for which your relation can relate to more than one element of the second set, then Jonny, that is not a function.
In the present case, every student ID number can only be realted to a number of the set {9, 10, 11, 12}, a student cannot have more than one current grade level. Therefore, that relation is in fact a function
Answer: 0.9104
Step-by-step explanation:
Given : A hardware store receives a shipment of bolts that are supposed to be 12 cm long.
Mean : 
Standard deviation : 
Sample size : n=10
Since, they will declare the shipment defective and return it to the manufacturer if the average length of the 100 bolts is less than 11.97 cm or greater than 12.04 cm.
So for the shipment to be satisfactory, the length of the bolts must be between 11.97 cm and 12.04 cm.
We assume that the length of the bolts are normally distributed.
Let X be the random variable that represents the length of randomly picked bolt .
For Z score : 
For x = 11.97
For x = 12.04
By using the standard normal distribution table , the probability that the shipment is found satisfactory will be :-
Hence, the probability that the shipment is found satisfactory=0.9104
We assume the composite figure is a cone of radius 10 inches and slant height 15 inches set atop a hemisphere of radius 10 inches.
The formula for the volume of a cone makes use of the height of the apex above the base, so we need to use the Pythagorean theorem to find that.
h = √((15 in)² - (10 in)²) = √115 in
The volume of the conical part of the figure is then
V = (1/3)Bh = (1/3)(π×(10 in)²×(√115 in) = (100π√115)/3 in³ ≈ 1122.994 in³
The volume of the hemispherical part of the figure is given by
V = (2/3)π×r³ = (2/3)π×(10 in)³ = 2000π/3 in³ ≈ 2094.395 in³
Then the total volume of the figure is
V = (volume of conical part) + (volume of hemispherical part)
V = (100π√115)/3 in³ + 2000π/3 in³
V = (100π/3)(20 + √115) in³
V ≈ 3217.39 in³
.0091 rounded to the nearest thousandths would be .009
