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2 years ago

Help, please! I will try to give you Brainliest when you get it right.

Mathematics

1 answer:

Amanda [17]2 years ago

6 0

Step-by-step explanation:

As,

x + 14 + 3x = 90 [Complementary Angles]

=> 4x = 90 - 14

=> 4x = 76

$= > x = \frac{76}{4}$

=> x = 19

Hence,

<1 = x + 14°

 = 19 + 14 = 33°

<2 = 3x

 = 3 × 19° = 57°

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A circle has the equation x^2+y^2+x-6y+9=0. Find the center and any x or y intercepts.

Softa [21]

We know:x^2+y^2+x−6y+9=0So, we complete the square as such:x^2+y^2+x−6y+9=x^2+x+y^2−6y+9=(x+1/2)^2+(y−3)^2=(1/2)^2=1/4

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3 years ago

Combine the like to simplify the expression: -5y + 12 + 8y − 6 − 2 =

ANTONII [103]

First, let's move combine like terms:

-5y + 8y = 6 + 2 -12.

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3 years ago

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Answer:

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2 years ago

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hodyreva [135]

Step-by-step explanation:

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3 years ago

The equation of a circle is given below.

BARSIC [14]

Given:

The equation of the circle is $x^2+(y+4)^2=64$

We need to determine the center and radius of the circle.

Center:

The general form of the equation of the circle is $(x-h)^2+(y-k)^2=r^2$

where (h,k) is the center of the circle and r is the radius.

Let us compare the general form of the equation of the circle with the given equation $x^2+(y+4)^2=64$ to determine the center.

The given equation can be written as,

$(x-0)^2+(y+4)^2=64$

Comparing the two equations, we get;

(h,k) = (0,-4)

Therefore, the center of the circle is (0,-4)

Radius:

Let us compare the general form of the equation of the circle with the given equation $x^2+(y+4)^2=64$ to determine the radius.

Hence, the given equation can be written as,

$x^2+(y+4)^2=8^2$

Comparing the two equation, we get;

$r^2=8^2$

$r=8$

Thus, the radius of the circle is 8

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3 years ago