Write a cubic function with zeros of -3, -5 and 2
1 answer:
For zeroes of r1,r2,r3, the factors of the function, f(x) are
(x-r1)(x-r2)(x-r3)
zeroes of -3,-5,2
(x-(-3))(x-(-5))(x-2)=
(x+3)(x+5)(x-2)
f(x)=(x+3)(x+5)(x-2)
expanded
f(x)=x³+6x²-x-30
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