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damaskus [11]
3 years ago
12

Write a cubic function with zeros of -3, -5 and 2

Mathematics
1 answer:
Lady bird [3.3K]3 years ago
5 0
For zeroes of r1,r2,r3, the factors of the function, f(x) are
(x-r1)(x-r2)(x-r3)

zeroes of -3,-5,2
(x-(-3))(x-(-5))(x-2)=
(x+3)(x+5)(x-2)

f(x)=(x+3)(x+5)(x-2)
expanded
f(x)=x³+6x²-x-30
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With
Hatshy [7]
<span>y - 2418.6 = 5.9(x - 54)
y - 2418.6 = 5.9x - 318.6
y = 5.9x + 2100 
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Now we can answer:
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 (Put me as brainiest!!!! <3)</span>
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