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3 years ago

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Peaches are being sold for $2 per pound. If x represents the number of pounds of peaches bought and y represents the total cost

of the peaches, which best describes the values of x and y?

1 answer:

Natalija [7]3 years ago

8 0

Y the cost is represented by 2x since each pear costs 2 dollars so you multiply how many pears you have by two to find the total cost or y=2x

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E=VIT how would I isolate the “V” variable

Zigmanuir [339]

Answer:

$V =\frac{E}{IT}$

Step-by-step explanation:

You can isolate the "V" variable by dividing by IT on both sides:

$\frac{E}{IT} =\frac{VIT}{IT}$

On the left, the IT from the top and bottom cancel, leaving you with just V:

$V =\frac{E}{IT}$

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What are all the factors of 45

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A guidance counselor at a university is investigating demand for study abroad. The question before her is how engineering and hu

Margaret [11]

Answer:

$\mu_{p_E -p_H} = 0.4-0.6 =-0.2$

$SE_{p_E -p_H}=\sqrt{\frac{0.4(1-0.4)}{20} +\frac{0.6 (1-0.6)}{20}}=0.1549$

b. Normal with mean μ= -0.2 and standard deviation σ=0.1549

Step-by-step explanation:

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$p_E$ represent the real population proportion for Engineering

$\hat p_E =\frac{8}{20}=0.4$ represent the estimated proportion for Engineering

$n_E=20$ is the sample size required for Engineering

$p_H$ represent the real population proportion for Humanities

$\hat p_H =\frac{12}{20}=0.6$ represent the estimated proportion for Humanities

$n_H=20$ is the sample size required for Humanities

We assume that the population proportions follows a normal distribution since we satisfy these conditions:

$np\geq 5$ , $n(1-p)\geq 5$

$20*0.4= 8\geq 5 , 20(1-0.4)=12\geq 5$

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

And we are interested on the distribution for $p_E-p_H$

For this case we know that the distribution for the differences of proportions is also normal and given by:

$p_E -p_H \sim N(\hat p_E -\hat p_H, \sqrt{\frac{\hat p_E(1-\hat p_E)}{n_E} +\frac{\hat p_H (1-\hat p_H)}{n_H}}$

So then we can find the mean and the deviation like this:

$\mu_{p_E -p_H} = 0.4-0.6 =-0.2$

$SE_{p_E -p_H}=\sqrt{\frac{0.4(1-0.4)}{20} +\frac{0.6 (1-0.6)}{20}}=0.1549$

So then the best option is :

b. Normal with mean μ= -0.2 and standard deviation σ=0.1549

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3 years ago

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vesna_86 [32]

Answer:

the length is 84 ft

Step-by-step explanation:

65*2= 130

298-130=168

168/2=84

84+84+65+65=298 ft

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Brut [27]

76% = 76 / 100 = 0.76

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= 76% * 670

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2 years ago

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