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Semmy [17]
3 years ago
15

Given that P = (-7, 16) and Q = (-8, 7), find the component form and magnitude of vector QP .

Mathematics
1 answer:
Katyanochek1 [597]3 years ago
7 0

Answer:

a)The component form is

\vec {QP}=\binom{ - 1}{ - 8}

b)The magnitude is √65

c) <2,14>

Step-by-step explanation:

Recall that:

\vec {QP}=\vec {OP}-\vec{OQ}

We substitute the position vectors to get:

\vec {QP}=\binom{ - 8}{7} -  \binom { - 7}{15}

We subtract the corresponding components to obtain:

\vec {QP}=\binom{ - 8 -  - 7}{7 - 15}

This gives:

\vec {QP}=\binom{ - 8  + 7}{7 - 15}

This simplifies to:

\vec {QP}=\binom{ - 1}{ - 8}

The magnitude of a vector in the component form:

\binom{x}{y}

is

\sqrt{ {x}^{2}  +  {y}^{2} }

This means:

|\vec {QP}|= \sqrt{ {( - 1)}^{2}  +  {( - 8)}^{2} }

This simplifies to:

|\vec {QP}| = \sqrt{ 1 +  64 }

|\vec {QP}| = \sqrt{ 65 }

c) We have the vectors u = <4, 8>, v = <-2, 6>.

We want to find:

u+v

This implies that:

u+v=<4,8>+<-2,6>

We add the corresponding components to get;

u+v=<4+-2,8+6>

This simplifies to:

u+v=<2,14>

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