Question

Given that P = (-7, 16) and Q = (-8, 7), find the component form and magnitude of vector QP .

Answer 1

Answer:

a)The component form is

$\vec {QP}=\binom{ - 1}{ - 8}$

b)The magnitude is √65

c) <2,14>

Step-by-step explanation:

Recall that:

$\vec {QP}=\vec {OP}-\vec{OQ}$

We substitute the position vectors to get:

$\vec {QP}=\binom{ - 8}{7} - \binom { - 7}{15}$

We subtract the corresponding components to obtain:

$\vec {QP}=\binom{ - 8 - - 7}{7 - 15}$

This gives:

$\vec {QP}=\binom{ - 8 + 7}{7 - 15}$

This simplifies to:

$\vec {QP}=\binom{ - 1}{ - 8}$

The magnitude of a vector in the component form:

$\binom{x}{y}$

is

$\sqrt{ {x}^{2} + {y}^{2} }$

This means:

$|\vec {QP}|= \sqrt{ {( - 1)}^{2} + {( - 8)}^{2} }$

This simplifies to:

$|\vec {QP}| = \sqrt{ 1 + 64 }$

$|\vec {QP}| = \sqrt{ 65 }$

c) We have the vectors u = <4, 8>, v = <-2, 6>.

We want to find:

u+v

This implies that:

u+v=<4,8>+<-2,6>

We add the corresponding components to get;

u+v=<4+-2,8+6>

This simplifies to:

u+v=<2,14>