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goldfiish [28.3K]
3 years ago
9

The 24 colleges of interest to a high school senior include 8 that are expensive​ (tuition more than​ $20,000 per​ year), 8 that

are far from home​ (more than 200 miles​ away), and 5 that are both expensive and far from home.
A. If the student decides to select a college that is not expensive and within 200 miles of home, how many selections are possible?
B. If the student decides to attend a college that is not expensive and within 200 miles from home during his first two years of college, and then will transfer to a college that is not expensive but is far from home, how many selections of two colleges are possible?
Mathematics
1 answer:
Luda [366]3 years ago
3 0

Answer:

The correct answers are A. 13; B.39.

Step-by-step explanation:

There are 24 colleges (U) that meet the interest of a high school senior.

8 colleges are expensive, 8 are far (above 200 miles from home) and 5 are both expensive and far.

Think of a Venn Diagram where there are two classes namely A = number of expensive colleges and B = number of far colleges. and A ∩ B = 5.

There are 8 - 5 = 3 colleges that are only expensive ( A - B).

There are 8 - 5 = 3 colleges that are only far (200 miles from the house) (B - A).

There are 24 - 8 = 16 colleges that are not expensive (A complement).

There are 24 - 8 = 16 colleges that are not far (B complement).

A. The number of colleges that is not expensive and within 200 miles of home = U - A - (B - A) = 24 - 8 - 3 = 13.

B.The number of colleges that is not expensive and within 200 miles from home during his first two years of college, and then will transfer to a college that is not expensive but is far from home = choices for first type of college × choices for the second type of college = 13 × (A complement ∩ (B - A) = 13 × 3 = 39.

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A professor wishes to discover if seniors skip more classes than freshmen. Suppose he knows that freshmen skip 2% of their class
KIM [24]

Answer:

We conclude that seniors skip more than 2% of their classes at 0.01 level of significance.

Step-by-step explanation:

We are given that a professor wishes to discover if seniors skip more classes than freshmen. Suppose he knows that freshmen skip 2% of their classes.

He randomly samples a group of seniors and out of 2521 classes, the group skipped 77.

<u><em /></u>

<u><em>Let p = percentage of seniors who skip their classes.</em></u>

So, Null Hypothesis, H_0 : p \leq 2%   {means that seniors skip less than or equal to 2% of their classes}

Alternate Hypothesis, H_A : p > 2%   {means that seniors skip more than 2% of their classes}

The test statistics that will be used here is <u>One-sample z proportion</u> <u>statistics</u>;

                                   T.S.  = \frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }  ~ N(0,1)

where, \hat p = sample proportion of seniors who skipped their classes = \frac{77}{2521}

           n = sample of classes = 2521

So, <u><em>test statistics</em></u>  =  \frac{\frac{77}{2521} -0.02}{{\sqrt{\frac{\frac{77}{2521}(1-\frac{77}{2521})}{2521} } } } }

                               =  3.08

The value of the test statistics is 3.08.

Now at 0.01 significance level, <u>the z table gives critical value of 2.3263 for right-tailed test</u>. Since our test statistics is more than the critical value of z as 2.3263 < 3.08, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u>we reject our null hypothesis</u>.

Therefore, we conclude that seniors skip more than 2% of their classes.

6 0
4 years ago
Need help on this one
malfutka [58]

Answer:

3

Step-by-step explanation:

To simplify this expression, we will simply work with the numerator, then the denominator, and then the fraction as a whole, following PEMDAS.

Numerator:  12 - 6 + 5 * (-3)^2

= 12 - 6 + 5 * (9)

= 12 - 6 + 45

= 6 + 45

= 51

Denominator:  17

So our simplified fraction is as follows:

51/17

Which can be reduced to the whole number, 3.

Cheers.

3 0
3 years ago
You are comparing cell phones. The old model is 7/8 of an inch thick. The new model is 3/5 of an inch thick. How much thinner is
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3 0
3 years ago
Can the product of two irrational numbers be rational? Explain your answer and support with an example.
Gala2k [10]

Sample Response: Yes, the product can be rational. The best example for this to happen is if you take the square root of a non-perfect square and square it, or multiply it by itself. This “undoes” the squaring, so you get a whole number, e.g. √5x√5 = 5.


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lara31 [8.8K]

Answer: y=(8x)^{\frac{1}{3}} -1 or y=\sqrt[3]{8x} -1

Step-by-step explanation:

To find the inverse, you switch y with x and x with y. Then, you solve for y.

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x=\frac{1}{8} (y+1)^3          [multiply both sides by 8]

8x=(y+1)^3           [cube both sides]

\sqrt[3]{8x} =y+1             [subtract both sides by 1]

y=\sqrt[3]{8x} -1 or y=(8x)^{\frac{1}{3}} -1

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3 years ago
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