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alexdok [17]
2 years ago
12

A 3.00-kg rifle fires a 0.00500-kg bullet at a speed of 300 m/s. Which force is greater in magnitude:(i) the force that the rifl

eexerts on the bullet; or (ii) the force that the bulletexerts on the rifle?A. the force that the rifle exerts on the bulletB. the force that the bullet exerts on the rifleC. both forces have the same magnitudeD. not enough information given to decide
Physics
1 answer:
alekssr [168]2 years ago
7 0

Answer:

C. both forces have the same magnitude

Explanation:

Here the action force is equal to the reaction force in accordance with the Newton's third law of motion.

Also when we apply the conservation of momentum so that the momentum bullet and the momentum of the gun are equal and according to the second law of motion by Newton, we have force equal to the rate of change in momentum.

We have the equation for momentum as:

p=m.v

Newton's second law is Mathematically given as:

F=\frac{dp}{dt}

Momentum is constant and the reaction time is equal, so the force exerted will also be equal.

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Vector ????⃗ has a magnitude of 16.6 and is at an angle of 50.5∘ counterclockwise from the +x‑axis. Vector ????⃗ has a magnitude
natka813 [3]

Answer:

For vector u, x component = 10.558 and  y component =12.808

unit vector = 0.636 i+ 0.7716 j

For vector v, x component = 23.6316 and y component = -6.464

unit vector = 0.9645 i-0.2638 j

Explanation:

Let the vector u has magnitude 16.6

u makes an angle of 50.5° from x axis

So u_x=ucos\Theta =16.6\times cos50.5=10.558

Vertical component u_y=usin\Theta =16.6\times sin50.5=12.808

So vector u will be u = 10.558 i+12.808 j

Unit vector u=\frac{10.558i+12.808j}{\sqrt{10.558^2+12.808^2}}=0.636i+0.7716j

Now in second case let vector v has a magnitude of 24.5

Making an angle with -15.3° from x axis

So horizontal component v_x=vcos\Theta =24.5\times cos(-15.3)=23.6316

Vertical component v_y=vsin\Theta =24.5\times sin(-15.3)=-6.464

So vector v will be 23.6316 i - 6.464 j

Unit vector of v =\frac{23.6316i-6.464}{\sqrt{23.6316^2+6.464^2}}=0.9645i-0.2638j

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On a hot day, warm air on land rises and collides with cool air. Which of these weather conditions is most likely to follow?
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I think its......C. Hurricane

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mina [271]
One of the advantages is Cost efficiencies
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a student measure the mass of an 8 cm^3 block of brown sugar to be 12.9 g. what is the density of the brown sugar?
schepotkina [342]
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1 Cubic Centimeter = 0,000001 Cubic Meter
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12,9 g = 0,0129 kg


The density is 0,0129 kg/ 0,000008 m^3 = <span><u>1612,5 kg/m^3</u> </span>
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3 years ago
Which threats of the biodiversity is a result of plants and animals introduced to an ecosystem where they are not normally found
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hope this helps
 
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