To hit the target the crew drop the crate before the plane is directly over the target. It is because <span>because the cargo has forward velocity and therefore before it reaches the ground it travels some distance. The answer is A. Hope it helps. </span>
Answer:
C and D
Explanation:
A uniform probability model is a probabilistic model characterized by a uniform probability density function, or uniform distribution.
In common language, a uniform probability distribution means that all possible outcomes in the probability space have the same probability of occurrence.
So:
- A fair toss of coin every possible outcome (H,T) has probability 0.5. It is modeled by by a uniform discrete distribution.
- Randomly selected answer to an MCQ with four options would have probability of success 0.25 for every MCQ. It is modeled by by a uniform discrete distribution.
- Spinning a spinner with sections that are different sizes, each section would have different probabilities proportional to the coverage area on the. It is modeled by a non-uniform discrete distribution
- Pulling a red marble out of a bag with 6 red marbles, 3 green marbles, and 1 yellow marble. Each successive time a red marble is drawn the probability decreases. Hence, non uniform distribution.
- Spinning a spinner on which all sections are the same size. Each section would have similar probabilities proportional to the coverage area on the. It is modeled by a uniform discrete distribution .
Answer:
3.8 secs
Explanation:
Parameters given:
Acceleration due to gravity, g = 9.8 
Initial velocity, u = 11.76 m/s
Final velocity, v = 49 m/s
Using one of Newton's equations of linear motion, we have that:
where t = time of flight of arrow
The sign is positive because the arrow is moving downward, in the same direction as gravitational force.
Therefore:
The arrow was in flight for 3.8 secs
<span>By algebra, d = [(v_f^2) - (v_i^2)]/2a.
Thus, d = [(0^2)-(15^2)]/(2*-7)
d = [0-(225)]/(-14)
d = 225/14
d = 16.0714 m
With 2 significant figures in the problem, the car travels 16 meters during deceleration.</span>
