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artcher [175]
3 years ago
7

Tom kicks a soccer ball on a flat, level field giving it an initial speed of 20 m/s at an angle of 35 degrees above the horizont

al. a) How long will the ball be in the air? b) What maximum height will the ball attain? c) How far away from Tom will the ball land? d) What speed will the ball have in the instant just before it lands?
Physics
1 answer:
SVEN [57.7K]3 years ago
8 0

Answer:

(a) 2.34 s

(b) 6.71 m

(c) 38.35 m

(d) 20 m/s

Explanation:

u = 20 m/s, theta = 35 degree

(a) The formula for the time of flight is given by

T = \frac{2 u Sin\theta }{g}

T = \frac{2 \times 20 \times Sin35 }{9.8}

T = 2.34 second

(b) The formula for the maximum height is given by

H = \frac{u^{2} \times Sin^{2}\theta }{2g}

H = \frac{20^{2} \times Sin^{2}35 }{2 \times 9.8}

H  = 6.71 m

(c) The formula for the range is given by

R = \frac{u^{2} \times Sin 2\theta }{g}

R = \frac{20^{2} \times Sin 2 \times 35}{9.8}

R = 38.35 m

(d) It hits with the same speed at the initial speed.

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Explanation:

KE = (1/2)mv^2

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Answer:

17.5 m/s²

1.90476 seconds

Explanation:

t = Time taken

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s = Displacement

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Force

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Initial acceleration of the rocket is 17.5 m/s²

v=u+at\\\Rightarrow \frac{120}{3.6}=0+17.5t\\\Rightarrow t=\frac{\frac{120}{3.6}}{17.5}=1.90476\ s

Time taken by the rocket to reach 120 km/h is 1.90476 seconds

Change in the velocity of a rocket is given by the Tsiolkovsky rocket equation

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where,

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Answer:

I will answer in English.

Here we will use the relation

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Distance = 10m/s*0.5s = 5m

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time = 2.5s

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What was the acceleration of the 2 kg cart?
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