The speed of the roller coater at the bottom of the hill is 31 m/s.
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Speed of the roller coater at the bottom of the hill</h3>
Apply the principle of conservation of mechanical energy as follows;
K.E(bottom) = P.E(top)
¹/₂mv² = mgh
v² = 2gh
v = √2gh
where;
- v is the speed of the coater at bottom hill
- h is the height of the hill
- g is acceleration due to gravity
v = √(2 x 9.8 x 49)
v = 31 m/s
Thus, the speed of the roller coater at the bottom of the hill is 31 m/s.
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C.
Thanks me later, that's my answer.
Answer:
50 m/s
Explanation:
Angle = 60 degree
Horizontal component of velocity = 50 m/s
A projectile motion is the motion of an object in two dimensions under the influence of gravity.
In this case, the object has no acceleration along horizontal direction, it has acceleration in vertical direction which is equal to the acceleration due to gravity of earth.
When the projectile reaches at the maximum height it travels only along the horizontal and thus it has only horizontal velocity at that instant.
Thus, the velocity of teh projectile at maximum height is same as horizontal component of velocity that meas 50 m/s.
Answer:
a) Option D
b) Option A
Explanation:
a) Option D
Because a massive car will have more inertia which will make the car move faster but a massive car simultaneously will have more friction thereby restricting its movement in the forward direction. Hence, all the three cars will move equal distance.
b) Option A, Car F
Being most massive car, the frictional force required to stop the car will be highest.
Answer:
because potentil energy is redy to go but its bound up
And kinetic energy is in motion
Explanation: