Answer:
f(x) = x⁴-6x³-13x²+66x+72
Step-by-step explanation:
Factors are: (x+3)(x+1)(x-4)(x-6)
[(x+3)(x+1)][(x-4)(x-6)]
[x²+3x+x+3][x²-4x-6x+24]
(x²+4x+3)(x²-10x+24)
x⁴+4x³+3x²-10x³-40x²-30x+24x²+96x+72
f(x) = x⁴-6x³-13x²+66x+72

5 0

3 years ago

Pls help is it proportional????

Xelga [282]

Yes it is proportional

3 0

3 years ago

Assume that a procedure yields a geometric distribution where the probability of success is 63%. Use the geometric probability f

tigry1 [53]

Answer:

Option A - 0.003

Step-by-step explanation:

Given: Probability of success = 63%= 0.63

Probability of failure = 1-0.63=0.37

To find: Probability that the first success occurs after the sixth trial

Formula for calculating geometric probabilities:

If P(X >n) or the probability that it takes more than a certain number of trials to achieve the first success.

$P(X>n)=(1-p)^n$

where, X has a geometric distribution,p is the probability of success and (1-p) is the failure and possible values of X are 1, 2, 3, ....

Now, put values p=0.63, (1-p)= 0.37 , n=6 in the formula

$P(X>n)=(1-p)^n$

$P(X>6)=(0.37)^6$

$P(X>6)=0.0025$

$P(X>6)=0.003$

Therefore, Option A is correct

4 0

4 years ago

Help me with this ixl pleaseeeeeeeeee

Virty [35]

Step-by-step explanation:

J(-3,9)

k(-10,9)

L(-10,4)

M(-3,4)

6 0

3 years ago