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Oxana [17]
3 years ago
9

A hydrogen line in a star's spectrum

Physics
1 answer:
Serhud [2]3 years ago
5 0

Answer: V = 4.35 × 10^12 m/s

Explanation: To calculate Rigel velocity relative to us, we should use doppler effect formula.

Fo = (c ) / ( c - Vs) × f

Fo/f = (c ) / ( c - Vs)

4.26 × 10^10 = (3×10^8) 6.17×10^14/(3×10^8 - V)

4.26×10^10/6.17×10^14 = (3×10^8)/(3×10^8 - V)

6.9×10^-5 = (3×10^8)/(3×10^8 - V)

Cross multiply

20713.13 - 6.9×10^-5V = 3×10^8

Collect the like terms

6.9×10^-5V = 3×10^8 - 20713.13

6.9×10^-5V = 299979286.9

V = 299979286.9/6.9×10^-5

V = 4.3475 × 10^12 m/s

Therefore, Rigel's velocity relative to us is 4.3475 × 10^12 m/s

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Answer:

Vectors have a size and direction. Each of the existing vector quantity has a magnitude and a direction. Having direction along with the magnitude is the difference of a vector quantity from a scalar quantity. Vectors are indicates with arrows.

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A rolling ball has an initial velocity of 1.6 meters per second. if the ball has a constant acceleration of 0.33 meters per seco
lukranit [14]
We have:

Initial velocity (u) = 1.6 m/s
Constant acceleration (a) = 0.33 m/s²
Time (t) = 3.6 sec

There are five constant acceleration equations that would help us to find the velocity:

v=u+at
s=ut+ \frac{1}{2}at^2
s= \frac{1}{2}(u+v)t
v^2=u^2+2as
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Since we have u, a, t and we want v
We will use the first formula v=u+at

v=1.6+(0.33)(3.6)
v= 2.788 m/s
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3 years ago
Which has greater kinetic energy, a car traveling at 40 mph or a half-as-massive car traveling at 80 mph?
ziro4ka [17]

Answer:

The 80 mph car

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3 years ago
Step 2: Apply NEwton's second law Apply ∑Fy = may , what should ay be equal to, since the block doesn't move in the y direction
andrey2020 [161]

Answer:

∑Fy = 0, because there is no movement, N = m*g*cos (omega)

Explanation:

We can solve this problem with the help of a free body diagram where we show the respective forces in each one of the axes, y & x. The free-body diagram and the equations are in the image attached.

If the product of mass by acceleration is zero, we must clear the normal force of the equation obtained. The acceleration is equal to zero because there is no movement on the Y-axis.

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