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Oxana [17]
3 years ago
9

A hydrogen line in a star's spectrum

Physics
1 answer:
Serhud [2]3 years ago
5 0

Answer: V = 4.35 × 10^12 m/s

Explanation: To calculate Rigel velocity relative to us, we should use doppler effect formula.

Fo = (c ) / ( c - Vs) × f

Fo/f = (c ) / ( c - Vs)

4.26 × 10^10 = (3×10^8) 6.17×10^14/(3×10^8 - V)

4.26×10^10/6.17×10^14 = (3×10^8)/(3×10^8 - V)

6.9×10^-5 = (3×10^8)/(3×10^8 - V)

Cross multiply

20713.13 - 6.9×10^-5V = 3×10^8

Collect the like terms

6.9×10^-5V = 3×10^8 - 20713.13

6.9×10^-5V = 299979286.9

V = 299979286.9/6.9×10^-5

V = 4.3475 × 10^12 m/s

Therefore, Rigel's velocity relative to us is 4.3475 × 10^12 m/s

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Two metal spheres are hanging from nylon threads. When you bring the spheres close to each other, they tend to attract. Based on
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Explanation:

In the given question, the two metal spheres were hanged with the nylon thread.

When these two spheres were brought close together, they attracted each other. The attraction between these spheres is the result of the opposite charges between them.

The possible ways by which these two metal spheres can be charged are by induction that is touching the metal or by rubbing them.

During induction, the same charges are transferred to each sphere. In this case, either both the spheres will be negatively charged or positively charged.

It is not possible that after the sphere touch each other they will cling together because the same charge repels each other and during touching, if one sphere is neutral, then the charged one will transfer the same charge. And as we know that same charge repel each other therefore they will repel each other.

4 0
3 years ago
Which changes to observed time and length occur when objects approach the speed of light?
mixas84 [53]

Answer:

Time moves slower and length decreases.

Explanation:

3 0
3 years ago
A robot standing on a cliff shoots a ball upwards with an initial speed of 30 m/s. What is the height of the cliff given that th
valina [46]

Answer:

C 80 m

Explanation:

Given:

v₀ = 30 m/s

a = -10 m/s²

t = 8 s

Find: Δy

Δy = v₀ t + ½ at²

Δy = (30 m/s) (8 s) + ½ (-10 m/s²) (8 s)²

Δy = -80 m

The ball lands 80 m below where it started.  So the height of the cliff is 80 m.

5 0
3 years ago
Find an equation in x and y for the line tangent to the curve ()=4,()=cos() at the point where =4.
m_a_m_a [10]

An equation in x and y for the line tangent to the curve ()=4,()=cos() at the point where =4 is x(t)=2t+2,y(t)=t^4.

<h3>What is tangent?</h3>

In calculation, the digression line to a plane bend at a given point is the straight line that "simply contacts" the bend by then. Leibniz characterized it as the line through a couple of boundlessly close focuses on the bend. The chart of digression is intermittent, implying that it rehashes the same thing endlessly. In contrast to sine and cosine in any case, digression has asymptotes isolating every one of its periods. The space of the digression capability is all genuine numbers with the exception of at whatever point cos⁡(θ)=0, where the digression capability is vague. Assuming they stroll in an orderly fashion, they are fundamentally following a digression way for the shape that is made inside the fencing.

Learn more about tangent, refer:

brainly.com/question/12585907

#SPJ4

7 0
2 years ago
A solid nonconducting sphere of radiusRcarries a chargeQdistributed uniformly throughout itsvolume. At a certain distancer1(r1&l
lara [203]

Answer:

E' = \frac{1}{8} E

Explanation:

Given data:

first case

Distance of electric field from center of sphere is r_1 <R

Electric field at r_1< R

E = \frac{kQr_1}{R^3}

second case

Distance of electric field from centre of sphere is r_1 < 2R

Electric field at r_1< 2R

E' = \frac{kQr_1}{8R^3}

so, we have

E' = \frac{1}{8} E

3 0
3 years ago
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