Given: Mass m = 44 Kg; Velocity v = 10 m/s
Required: Kinetic energy K.E = ?
Formula: K.E = 1/2 mv²
K.E 1/2 (44 Kg)(10 m/s)²
K.E = 2,200 Kg.m²/s²
K.E = 2,200 J Answer is A
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Answer: 2.1 × 10^7 m/s
Explanation:
Please see the attachments below
Answer:
165.77J
Explanation:
M₁ = 0.107kg
u₁ = 300m/s
m₂ = 3kg
u₂ = 0
v =
m₁u₁ + m₂u₂ = (m₁ + m₂)V
(0.107*300) + 0 = (0.107 + 3)V
V = 32.1 / 3.107 = 10.33m/s
kinetic energy of the system after collision =
½m1v² + ½m2v²
K.E = ½(m1 + m2)v²
K.E = ½(0.107+3) * 10.33²
K.E = 165.77J