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sleet_krkn [62]
2 years ago
7

Find the center of mass of a one-meter long rod, made of 50 cm of iron (density 8gcm3) and 50 cm of aluminum (density 2.7gcm3).

Physics
1 answer:
alexdok [17]2 years ago
4 0

The center of the mass of a one-meter long rod, made of 50 cm of iron (density 8gcm3) and 50 cm of aluminum (density 2.7gcm3) is 37.62(cm)

<h3>Calculations and Parameters</h3>

λ Fe =8g/cm,λ Al =2.7g/cm

There is a metal rod 1 meter long, with the first 50cm being iron and the other 50cm aluminum. the problem is solved in a one-dimensional case meaning it's a thin rod.

Next, we would solve by definition of the center of mass

We would also note that the masses of iron and aluminum are just the product of their length and linear density.

X_C_M= \frac{8(g/cm). \frac{2500(cm^2)}{2} + 2.7 (g/cm). \frac{7500(cm^2)}{2} }{8(g/cm).50(cm) + 2.7(g/cm). 50 (cm)}

= 37.62(cm)

Read more about center of mass here:

brainly.com/question/13499822

#SPJ1

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The distance and direction between starting and ending positions​
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Answer:

The length traveled by an object moving in any direction or even changing direction is called distance. The location of an object in a frame of reference is called position. For straight line motion, positions can be shown using a number line. The separation between original and final position is called displacement

Explanation:

good luck

8 0
3 years ago
What is the current in a series circuit that has two resistors (4.0 ohms and 7.5 ohms) and a power source of 9.0 volts?
Olin [163]

-- First, we have to decide how to handle the two resistors.

The effective resistance of resistors in series is the sum
of their individual resistances.  That is, they act like a single
resistor, whose resistance is the sum of all of them.

So in this question, the 4.0 ohms and the 7.5 ohms act like a
single resistor of 11.5 ohms.

-- The current in the circuit is

                       (the supply voltage) / (the total resistance)

                   =                (9.0 volts)  /  (11.5 ohms)

                   =                      0.783... Ampere        (rounded)

3 0
3 years ago
Read 2 more answers
If a child starts from rest at point A and lands in the water at point B, a horizontal distance L = 2.52 m from the base of the
tamaranim1 [39]

Answer:

The height of the water slide is 0.878 m

Explanation:

Given that,

Distance = 2.52 m

Suppose Children slide down a friction less water slide that ends at a height of 1.80 m above the pool.

We need to calculate the time

Using equation of motion

s=ut+\dfrac{1}{2}gt^2

Put the value in the equation

1.80=0+\dfrac{1}{2}\times9.8\times t^2

t^2=\dfrac{1.80\times2}{9.8}

t=\sqrt{\dfrac{1.80\times2}{9.8}}

t=0.606\ sec

We need to calculate the velocity

Using formula of velocity

v = \dfrac{d}{t}

Put the value into the formula

v=\dfrac{2.52}{0.606}

v=4.15\ m/s

We need to calculate height

Using conservation of energy

\dfrac{1}{2}mv^2=mgh

h=\dfrac{v^2}{2g}

Put the value into the formula

h=\dfrac{4.15^2}{2\times9.8}

h=0.878\ m

Hence, The height of the water slide is 0.878 m.

4 0
2 years ago
Can I get a direct answer please??
OleMash [197]
Get a direct answer of what???
7 0
3 years ago
What happens to light when it changes speed?
Brut [27]
Hey there!

When light changes speed, it REFRACTS.
Your answer is going to be option C.

Hope this helps you.
Have a great day!
5 0
3 years ago
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