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3 years ago

Find the equation of the line through the point (7,-6) with the slope -15/13

Mathematics

1 answer:

gayaneshka [121]3 years ago

3 0

Answer:

y + 6 = -15/13(x-7)

Step-by-step explanation:

Substitute m= -15/13 and the point (7,-6) into the point slope form.

y --6 = -15/13 (x - 7)

y + 6 = -15/13(x-7)

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A = {1, 3, 5, 7, 9}

kondor19780726 [428]

The $\cap$ symbol means intersection, so everything that is in both sets, and the $\cup$ symbol means union, so the two sets combined.

$B \cup C = \{1, 2, 4, 5, 6, 7, 8, 9, 10\} = S$
$A \cap S= \{1, 5, 7, 9\}$

So the answer is A.

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3 years ago

What is the value of y in the equation y = 3x - 2, when x = 2

Travka [436]

Answer:

y=4

Step-by-step explanation:

3 x 2=6

6 - 2= 4

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3 years ago

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Referring to triangle ABC, find the area of the triangle.

kondaur [170]

Answer:

$Area = 337$

Step-by-step explanation:

Given

$a = 42.5$

$c = 35.5$

$B = 153.5^\circ$

Required

Area of triangle

This is calculated as:

$Area = 0.5 *a* c * \sin(B)$

This gives:

$Area = 0.5 *42.5* 35.5 * \sin(153.5)$

$Area = 0.5 *42.5* 35.5 * 0.4462$

$Area = 336.602125$

$Area = 337$ --- approximated

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3 years ago

What is equivalent to a+a?

chubhunter [2.5K]

Answer:

Step-by-step explanation:

We can combine like terms.

There are 2 'a' s in the expression, so we can rewrite a + a as 2a.

3 0

3 years ago

Find, to the nearest tenth, the area of the region that is inside the square and outside the circle. the diameter of the circle

Doss [256]

Answer:

Option $42.1\ in^{2}$

Step-by-step explanation:

we know that

The area of the region that is inside the square and outside the circle is equal to the area of the square minus the area of the circle

see the attached figure to better understand the problem

Step 1

Find the area of the square

Remember that

The area of the square is

$A=b^{2}$

where

b is the length side of the square

we have

$b=14\ in$

substitute

$A=14^{2}=196\ in^{2}$

Step 2

Find the area of the circle

Remember that

The area of the circle is equal to

$A=\pi r^{2}$

we have

$r=14/2=7\ in$

substitute

$A=\pi(7^{2})=153.9\ in^{2}$

Step 3

Find the area of the region

$196\ in^{2}-153.9\ in^{2}=42.1\ in^{2}$

5 0

3 years ago

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